【发布时间】:2016-11-11 04:01:27
【问题描述】:
我想知道如何编写一个递归程序来定位由起始路径指示的 Java 文件。它应该在树中搜索指定的文件。如果找到文件,则应返回文件的位置。这是我到目前为止所拥有的(不多,仍然需要基本清理)。我需要使用这些确切的方法。我最困惑的是什么方法。所以我知道我需要使用:
File f = new File(dirName);
String [] fileList = f.list();
File aFile = new File (dirName + "\\" + fileList[i]);
if (aFile.isDirectory()) {...}
public class FindFile {
如果你能帮我弄清楚这些方法中的每一个都是什么方法,那将是一个了不起的帮助!!!我只是不太了解每种方法的逻辑。我还有一个需要使用的另一个类的驱动程序。
/**
* This constructor accepts the maximum number of files to find.
*/
public FindFile (int maxFiles)
{
}
/**
* The parameters are the target file name to look for and the directory to start in.
* @param target = target file name, dirName = directory to start in
*/
public void directorySearch (String target, String dirName) {
File f = new File(dirName);
String [] fileList = f.list();
File aFile = new File(dirName + "\\" + fileList[i]);
if (aFile.isDirectory()) {
}
else {
}
}
/**
* This accessor returns the number of matching files found.
* @return number of matching files found
*/
public int getCount () {
return -1;
}
/**
* This getter returns the array of file locations, up to maxFiles in size.
* @return array of file locations
*/
public String [] getFiles () {
return new String[] {""};
}
/**
* Prompt the user for max number of files to look for, the directory to start in, and the file name.
* Then, print out the list of found files with the full path name to the file (including starting
* directory). In the event of an exception being thrown, driver catches it and provides an appropriate
* message to the user.
*/
public static void main (String [] args) {
Scanner keyboard = new Scanner(System.in);
System.out.println("What is the max number of files to look for?");
System.out.println("What directory should we start in?");
Systme.out.println("What is the file name?");
}
}
【问题讨论】: