【发布时间】:2011-02-09 06:45:58
【问题描述】:
我正在使用下面的代码来获取搜索结果。当我在谷歌中插入字符串时,我得到一个搜索结果,但是当我试图通过代码获取结果时,它什么也不返回。谁能解释为什么代码不起作用。如果我输入其他搜索词,它会返回结果
<?php
$string="make them see things from your view";
$request = trim("http://ajax.googleapis.com/ajax/services/search/web");
$referrer = trim("http://localhost/");
$version = "1.0";
$getargs = '?v='. $version .'&rsz=small&q="'. urlencode($string).'"' ;
// Get the curl session object
$session = curl_init($request . $getargs);
// Set the GET options.
curl_setopt($session, CURLOPT_HTTPGET, true);
curl_setopt($session, CURLOPT_HEADER, true);
curl_setopt($session, CURLOPT_RETURNTRANSFER, true);
curl_setopt($session, CURLOPT_REFERER, $referrer);
//var_dump $response;
$response=null;
// Do the POST and then close the session
$response = curl_exec($session);
curl_close($session);
var_dump ($response);
// Get HTTP Status code from the response
$status_code = array();
preg_match('/\d\d\d/', $response, $status_code);
print_r($status_code);
?>
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