【问题标题】:How can I not get a base 10 error from a user input in Python GUI?如何从 Python GUI 中的用户输入中获取 base 10 错误?
【发布时间】:2019-03-25 03:24:56
【问题描述】:

我正在尝试使用带有 Python 的 GUI 来创建一个带有整数输入的简单函数。

我对 GUI 概念真的很陌生,所以我不知道还能做什么。

from tkinter import *

root = Tk()

peopleText = Label(root, text="How many people are in your household? ")
wageText = Label(root, text="How much do you make a month before deductions? ")

peopleInput = Entry(root)
wageInput = Entry(root)

runButton = Button(root, text="Run")

peopleText.grid(row=1, column=0)
wageText.grid(row=2, column=0)
peopleInput.grid(row=1, column=1)
wageInput.grid(row=2, column=1)

def runProcess():
    incomeSNAP = int(peopleInput.get()) - 1
    incomeHousing = int(peopleInput.get()) - 1
    if int(wageInput.get()) <= incomeSNAP:
        print("Yes")
    else:
        print("No")
    if int(wageInput.get()) <= incomeHousing:
        print("Yes")
    else:
        print("No")

runButton = Button(root, text="Run")
runButton.bind('<Button_1>', runProcess())
runButton.pack()

root.mainloop()

我希望会弹出一个窗口,但出现此错误:

  File "/Users/noahpark/PycharmProjects/pythonProject/gui.py", line 21, in runProcess
    incomeSNAP = int(peopleInput.get()) - 1
ValueError: invalid literal for int() with base 10: ''

【问题讨论】:

  • 还有很多问题需要处理,但是对于你的具体错误,需要去掉runButton.bind('&lt;Button_1&gt;', runProcess())上的(),因为你需要提供函数的引用。传递runProcesss() 将立即执行该函数。也应该是&lt;Button-1&gt;
  • 您要查找的神奇关键字是tryexcept

标签: python user-interface


【解决方案1】:

发现问题是如果您注释掉代码中的'&lt;Button_1&gt;' and .pack(),然后将command=runProcess 添加到它应该运行的按钮中。

from tkinter import *

root = Tk()

peopleText = Label(root, text="How many people are in your household? ")
wageText = Label(root, text="How much do you make a month before deductions? ")

peopleInput = Entry(root)
wageInput = Entry(root)

runButton = Button(root, text="Run")

peopleText.grid(row=1, column=0)
wageText.grid(row=2, column=0)
peopleInput.grid(row=1, column=1)
wageInput.grid(row=2, column=1)

def runProcess():
    incomeSNAP = int(peopleInput.get()) - 1
    incomeHousing = int(peopleInput.get()) - 1
    if int(wageInput.get()) <= incomeSNAP:
        print("Yes")
    else:
        print("No")
    if int(wageInput.get()) <= incomeHousing:
        print("Yes")
    else:
        print("No")



runButton = Button(root, text="Run", command=runProcess)
runButton.grid(row=3, column=0)
#runButton.bind('<Button_1>', runProcess())
#runButton.pack()

root.mainloop()

再补充一点,当用户输入错误的变量比如“字符串”时,你可以捕捉到值错误

from tkinter import *


root = Tk()

peopleText = Label(root, text="How many people are in your household? ")
wageText = Label(root, text="How much do you make a month before deductions? ")

peopleInput = Entry(root)
wageInput = Entry(root)

runButton = Button(root, text="Run")

peopleText.grid(row=1, column=0)
wageText.grid(row=2, column=0)
peopleInput.grid(row=1, column=1)
wageInput.grid(row=2, column=1)

def runProcess():
    try:
        peopleValue = int(peopleInput.get())
        wageValue = int(peopleInput.get())
    except ValueError:
        peopleValue = None
        wageValue = None
        print("Pls input integer")
        return

    incomeSNAP = int(peopleInput.get()) - 1
    incomeHousing = int(peopleInput.get()) - 1
    if int(wageInput.get()) <= incomeSNAP:
        print("Yes")
    else:
        print("No")
    if int(wageInput.get()) <= incomeHousing:
        print("Yes")
    else:
        print("No")




runButton = Button(root, text="Run", command=runProcess)
runButton.grid(row=3, column=0)


root.mainloop()

希望有帮助

【讨论】:

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