【发布时间】:2016-06-14 11:26:25
【问题描述】:
我正在尝试从我的 XML 数组中获取 1 个值。
这是代码:
<?php
function objectsIntoArray($arrObjData, $arrSkipIndices = array())
{
$arrData = array();
// if input is object, convert into array
if (is_object($arrObjData)) {
$arrObjData = get_object_vars($arrObjData);
}
if (is_array($arrObjData)) {
foreach ($arrObjData as $index => $value) {
if (is_object($value) || is_array($value)) {
$value = objectsIntoArray($value, $arrSkipIndices); // recursive call
}
if (in_array($index, $arrSkipIndices)) {
continue;
}
$arrData[$index] = $value;
}
}
return $arrData;
}
?>
Result:
<?php
$xmlUrl = "http://radiourl:port/status.xsl"; // XML feed file/URL
$xmlStr = file_get_contents($xmlUrl);
$xmlObj = simplexml_load_string($xmlStr);
$arrXml = objectsIntoArray($xmlObj);
print_r($arrXml);
?>
print_r($arrXml); 的结果这是:
Array (
[Mount-Point] => /listen.mp3
[Stream-Title] => VibboStream
[Stream-Description] => name
[Content-Type] => audio/mpeg
[Mount-started] => 14/Jun/2016:04:28:49 -0500
[Bitrate] => 128
[Current-Listeners] => 1
[Peak-Listeners] => 3
[Stream-Genre] => Various
[Stream-URL] => http://url [ice-bitrate] => 128
[icy-info] => ice-samplerate=44100;ice-bitrate=128;ice-channels=2
[Current-Song] => Artist - Title
)
所以我想要得到的是 [Current-Song] => Artist - Title 部分。 当我回应它时,我只想看到 Artist - Title
有人可以帮我解决这个问题吗?
【问题讨论】: