【发布时间】:2021-01-07 12:10:27
【问题描述】:
我正在尝试解压缩存储在 Azure Blob 容器中的受密码保护的文件。我想在 Azure Blob 本身上提取它。我已经使用 Python 创建了一个 Azure Function App(目前它是基于 Timer Control 事件的)来测试东西 -
以下是我的代码 - 我不确定实现此目的的正确方法是什么
import datetime
import os, uuid
import azure.functions as func
import azure.storage.blob
from zipfile import ZipFile
from azure.storage.blob import BlobServiceClient, BlobClient, ContainerClient
def test_func():
#get connection string to storage account
connect_str = os.getenv('AZURE_STORAGE_CONNECTION_STRING')
# BlobServiceClient object which will be used refer to a container client
blob_service_client = BlobServiceClient.from_connection_string(connect_str)
# Create a unique name for the container
container_name = "zipextract"
container_client = blob_service_client.get_container_client(container_name)
blob_list = container_client.list_blobs()
for blob in blob_list:
print("----> " + blob.name)
with ZipFile(blob.name) as zf:
zf.extractall(pwd=b'password')
现在,当我尝试使用 ZipFile() 函数访问文件时 - 它显示“没有这样的文件或目录:'TestZip.zip'”。
以下是错误消息 - (TestZip.zip 是放置在 zipextract 容器上的 zip 文件)
Result: Failure Exception: FileNotFoundError: [Errno 2] No such file or
directory: 'TestZip.zip' Stack: File "/azure-functions-
host/workers/python/3.8/LINUX/X64/azure_functions_worker/dispatcher.py", line
271, in _handle__function_load_request func = loader.load_function( File
"/azure-functions-
host/workers/python/3.8/LINUX/X64/azure_functions_worker/utils/wrappers.py",
line 32, in call return func(*args, **kwargs) File "/azure-functions-
host/workers/python/3.8/LINUX/X64/azure_functions_worker/loader.py", line 76,
in load_function mod = importlib.import_module(fullmodname) File
"/usr/local/lib/python3.8/importlib/__init__.py", line 127, in import_module
return _bootstrap._gcd_import(name[level:], package, level) File "<frozen
importlib._bootstrap>", line 1014, in _gcd_import File "<frozen
importlib._bootstrap>", line 991, in _find_and_load File "<frozen
importlib._bootstrap>", line 961, in _find_and_load_unlocked File "<frozen
importlib._bootstrap>", line 219, in _call_with_frames_removed File "<frozen
importlib._bootstrap>", line 1014, in _gcd_import File "<frozen
importlib._bootstrap>", line 991, in _find_and_load File "<frozen
importlib._bootstrap>", line 975, in _find_and_load_unlocked File "<frozen
importlib._bootstrap>", line 671, in _load_unlocked File "<frozen
importlib._bootstrap_external>", line 783, in exec_module File "<frozen
importlib._bootstrap>", line 219, in _call_with_frames_removed File
"/home/site/wwwroot/TimerTrigger1/__init__.py", line 39, in <module>
test_func() File "/home/site/wwwroot/TimerTrigger1/__init__.py", line 33, in
test_func with ZipFile(blob.name) as zf: File
"/usr/local/lib/python3.8/zipfile.py", line 1251, in __init__ self.fp =
io.open(file, filemode)
关于如何解压缩此文件的任何帮助?解压缩在本地机器上运行良好,但是,不知道如何让它运行,以便它引用 blob 而不是本地文件。
谢谢。
【问题讨论】:
-
能否详细提供错误信息?
-
@JimXu - 我添加了错误消息。似乎 ZipFile(blob.name) 不是指 blob 容器上的 zip 文件。我需要完整路径吗?
标签: python-3.x azure azure-functions azure-function-app