如何修复emailcheck python脚本中的输出错误

Question

我正在尝试使用 python 脚本在 gmail 上做监听器以获取具有特定标准的传入电子邮件到目前为止一切正常脚本因此监听器并等待预期的电子邮件但是当电子邮件被接收时我得到以下错误任何帮助将受到欢迎，我也是初学者。已经谢谢了。 使用的脚本：

import time
from itertools import chain
import email
import imaplib

imap_ssl_host = 'imap.gmail.com'  # imap.mail.yahoo.com
imap_ssl_port = 993
username = 'USERNAME or EMAIL ADDRESS'
password = 'PASSWORD'

# Restrict mail search. Be very specific.
# Machine should be very selective to receive messages.
criteria = {
    'FROM':    'PRIVILEGED EMAIL ADDRESS',
    'SUBJECT': 'SPECIAL SUBJECT LINE',
    'BODY':    'SECRET SIGNATURE',
}
uid_max = 0


def search_string(uid_max, criteria):
    c = list(map(lambda t: (t[0], '"'+str(t[1])+'"'), criteria.items())) + [('UID', '%d:*' % (uid_max+1))]
    return '(%s)' % ' '.join(chain(*c))
    # Produce search string in IMAP format:
    #   e.g. (FROM "me@gmail.com" SUBJECT "abcde" BODY "123456789" UID 9999:*)


def get_first_text_block(msg):
    type = msg.get_content_maintype()

    if type == 'multipart':
        for part in msg.get_payload():
            if part.get_content_maintype() == 'text':
                return part.get_payload()
    elif type == 'text':
        return msg.get_payload()


server = imaplib.IMAP4_SSL(imap_ssl_host, imap_ssl_port)
server.login(username, password)
server.select('INBOX')

result, data = server.uid('search', None, search_string(uid_max, criteria))

uids = [int(s) for s in data[0].split()]
if uids:
    uid_max = max(uids)
    # Initialize `uid_max`. Any UID less than or equal to `uid_max` will be ignored subsequently.

server.logout()


# Keep checking messages ...
# I don't like using IDLE because Yahoo does not support it.
while 1:
    # Have to login/logout each time because that's the only way to get fresh results.

    server = imaplib.IMAP4_SSL(imap_ssl_host, imap_ssl_port)
    server.login(username, password)
    server.select('INBOX')

    result, data = server.uid('search', None, search_string(uid_max, criteria))

    uids = [int(s) for s in data[0].split()]
    for uid in uids:
        # Have to check again because Gmail sometimes does not obey UID criterion.
        if uid > uid_max:
            result, data = server.uid('fetch', uid, '(RFC822)')  # fetch entire message
            msg = email.message_from_string(data[0][1])
            
            uid_max = uid
        
            text = get_first_text_block(msg)
            print 'New message :::::::::::::::::::::'
            print text

    server.logout()
    time.sleep(1)

结果：

C:\Users\PC Sony>"C:/Users/PC Sony/AppData/Local/Programs/Python/Python38/python.exe" "c:/Users/PC Sony/Desktop/elzero/elzero/# import PySimpleGUI.py"
Traceback (most recent call last):
  File "c:/Users/PC Sony/Desktop/elzero/elzero/# import PySimpleGUI.py", line 68, in <module>
    result, data = server.uid('fetch', uid, '(RFC822)')  # fetch entire message
  File "C:\Users\PC Sony\AppData\Local\Programs\Python\Python38\lib\imaplib.py", line 881, in uid
    typ, dat = self._simple_command(name, command, *args)
  File "C:\Users\PC Sony\AppData\Local\Programs\Python\Python38\lib\imaplib.py", line 1205, in _simple_command
    return self._command_complete(name, self._command(name, *args))
  File "C:\Users\PC Sony\AppData\Local\Programs\Python\Python38\lib\imaplib.py", line 963, in _command
    data = data + b' ' + arg
TypeError: can't concat int to bytes

Answer 1

result, data = server.uid('fetch', uid, '(RFC822)')

应该改为

result, data = server.uid('fetch', str(uid), '(RFC822)')

参数应该是字符串或字节类型。 imaplib.py 中的源代码

        for arg in args:
        if arg is None: continue
        if isinstance(arg, str):
            arg = bytes(arg, "ASCII")
        data = data + b' ' + arg