如何在建议恢复回调中获取 HTTP 状态

Question

我有一个简单的集成流程，它通过多次尝试向外部资源发送请求。我为此目的创建RequestHandlerRetryAdvice：

RequestHandlerRetryAdvice requestHandlerRetryAdvice = new RequestHandlerRetryAdvice();
requestHandlerRetryAdvice.setRecoveryCallback(retryContext -> {
    Message<?> failedMessage = ((MessagingException) retryContext.getLastThrowable()).getFailedMessage();
    //TODO: get http status
    return failedMessage.getPayload();
});

我需要知道的是 http 状态。我怎样才能得到它？

Answer 1

HTTP 状态是抛出异常的一部分：

((MessagingException) retryContext.getLastThrowable()).getCause() 应该包含一个带有getStatusCode() 属性的HttpStatusCodeException。

我的测试表明：

retryContext = ...
 lastException = org.springframework.messaging.MessagingException: ...
  failedMessage = ...
  backtrace = {Object[6]@7673} 
  detailMessage = "Failed to handle"
  cause = org.springframework.messaging.MessageHandlingException: ...
   failedMessage = ...
   cause = {HttpClientErrorException$Forbidden@7685} "org.springframework.web.client.HttpClientErrorException$Forbidden: 403 Forbidden: [no body]"
    statusCode = {HttpStatus@7690} "403 FORBIDDEN"
    rawStatusCode = 403
    statusText = "Forbidden"

代码是这样的：

.handle(Http.outboundGateway("/service/internal?{params}")
                                .uriVariable("params", "payload")
                                .expectedResponseType(String.class),
                        e ->  e.advice(retryAdvice()))

private RequestHandlerRetryAdvice retryAdvice() {
        RequestHandlerRetryAdvice requestHandlerRetryAdvice = new RequestHandlerRetryAdvice();
        requestHandlerRetryAdvice.setRecoveryCallback(retryContext -> {
            MessagingException lastThrowable = (MessagingException) retryContext.getLastThrowable();
            return ((HttpStatusCodeException) lastThrowable.getCause().getCause()).getStatusCode();
        });
        return requestHandlerRetryAdvice;
    }