解析来自 Google Geocode 的 json 响应答案

【问题标题】：Parsing json response from Google Geocode解析来自 Google Geocode 的 json 响应
【发布时间】：2017-08-13 06:22:30
【问题描述】：

我正在尝试解析来自 Google API 的响应。

我想知道是否有一种简单/有效的方法可以在 php 中解析这个数组以从“address_components”数组中获取数据。

{
   "results" : [
      {
     "address_components" : [
        {
           "long_name" : "10",
           "short_name" : "10",
           "types" : [ "street_number" ]
        },
        {
           "long_name" : "Downing Street",
           "short_name" : "Downing St",
           "types" : [ "route" ]
        },
        {
           "long_name" : "Westminster",
           "short_name" : "Westminster",
           "types" : [ "neighborhood", "political" ]
        },
        {
           "long_name" : "London",
           "short_name" : "London",
           "types" : [ "postal_town" ]
        },
        {
           "long_name" : "Greater London",
           "short_name" : "Greater London",
           "types" : [ "administrative_area_level_2", "political" ]
        },
        {
           "long_name" : "England",
           "short_name" : "England",
           "types" : [ "administrative_area_level_1", "political" ]
        },
        {
           "long_name" : "United Kingdom",
           "short_name" : "GB",
           "types" : [ "country", "political" ]
        },
        {
           "long_name" : "SW1A 2AA",
           "short_name" : "SW1A 2AA",
           "types" : [ "postal_code" ]
        }
     ],
     "formatted_address" : "10 Downing St, Westminster, London SW1A 2AA, UK",
     "geometry" : {
        "location" : {
           "lat" : 51.5033635,
           "lng" : -0.1276248
        },
        "location_type" : "ROOFTOP",
        "viewport" : {
           "northeast" : {
              "lat" : 51.5047124802915,
              "lng" : -0.126275819708498
           },
           "southwest" : {
              "lat" : 51.5020145197085,
              "lng" : -0.128973780291502
           }
        }
     },
     "place_id" : "ChIJRxzRQcUEdkgRGVaKyzmkgvg",
     "types" : [ "establishment", "point_of_interest" ]
  }
],
"status" : "OK"
}

我最初的方法是循环遍历数组并创建一个新数组并将键设置为“类型”，但我遇到了一些问题，即“类型”有多个选项

【问题讨论】：

你想要的输出是什么？
@RamRaider 我的目标是获得一个包含 "address_components" 数组的数组，其中 "types" 将是键，而 " long_name" 将是值。
javascript 不支持带有键名的数组 -
@RamRaider 我正在使用 PHP，所以响应是一个 json 数组并且将其输出到 assoc 数组
而types 有多个值，您会使用它们作为键吗？

标签： php arrays json google-maps google-api

【解决方案1】：

$data='{
   "results" : [
      {
     "address_components" : [
        {
           "long_name" : "10",
           "short_name" : "10",
           "types" : [ "street_number" ]
        },
        {
           "long_name" : "Downing Street",
           "short_name" : "Downing St",
           "types" : [ "route" ]
        },
        {
           "long_name" : "Westminster",
           "short_name" : "Westminster",
           "types" : [ "neighborhood", "political" ]
        },
        {
           "long_name" : "London",
           "short_name" : "London",
           "types" : [ "postal_town" ]
        },
        {
           "long_name" : "Greater London",
           "short_name" : "Greater London",
           "types" : [ "administrative_area_level_2", "political" ]
        },
        {
           "long_name" : "England",
           "short_name" : "England",
           "types" : [ "administrative_area_level_1", "political" ]
        },
        {
           "long_name" : "United Kingdom",
           "short_name" : "GB",
           "types" : [ "country", "political" ]
        },
        {
           "long_name" : "SW1A 2AA",
           "short_name" : "SW1A 2AA",
           "types" : [ "postal_code" ]
        }
     ],
     "formatted_address" : "10 Downing St, Westminster, London SW1A 2AA, UK",
     "geometry" : {
        "location" : {
           "lat" : 51.5033635,
           "lng" : -0.1276248
        },
        "location_type" : "ROOFTOP",
        "viewport" : {
           "northeast" : {
              "lat" : 51.5047124802915,
              "lng" : -0.126275819708498
           },
           "southwest" : {
              "lat" : 51.5020145197085,
              "lng" : -0.128973780291502
           }
        }
     },
     "place_id" : "ChIJRxzRQcUEdkgRGVaKyzmkgvg",
     "types" : [ "establishment", "point_of_interest" ]
  }
],
"status" : "OK"
}';

$json=json_decode( $data );
if( $json->status=='OK' ){

    $data=array();/* store results */

    $results=$json->results;
    foreach( $results as $index => $obj ){
        $add=$obj->address_components;
        foreach( $add as $address ){
            $data[ $obj->formatted_address ][ implode( '-', array_values( $address->types ) ) ]=$address->long_name;
        }
    }
    echo '<pre>',print_r($data,1),'</pre>';
}

将输出：

Array
(
    [10 Downing St, Westminster, London SW1A 2AA, UK] => Array
        (
            [street_number] => 10
            [route] => Downing Street
            [neighborhood-political] => Westminster
            [postal_town] => London
            [administrative_area_level_2-political] => Greater London
            [administrative_area_level_1-political] => England
            [country-political] => United Kingdom
            [postal_code] => SW1A 2AA
        )

)

【讨论】：

The decode() true version（没有array_values()）
课程用马——虽然我个人更喜欢使用对象表示法而不是数组表示法，但最终结果是一样的
不值得添加答案。你的方法完全没问题。我只是想展示另一种方式。很好的答案。