【发布时间】:2020-02-13 20:39:46
【问题描述】:
当我更改菜单显示选项时,如何将第二个下拉菜单更改为选择父菜单?
$(function() {
$('select').change(function(evt) {
console.log($('select option:selected').data('check'));
//$('select option:selected').data('check') ? $('#ifYes').show() : $('#ifYes').hide();
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div>
If I change the Menu Display automatically parent menu will be chaged?
</div>
<br>
<div class="form-group">
<label for="exampleInputEmail1">Menu Display</label>
<select name="status" class="form-control ">
<option value="1">Top Menu</option>
<option data-check="true" value="2">Sub Menu</option>
<option value="0">Footer Menu</option>
</select>
</div>
<div class="form-group " id="ifYes" style="">
<label for="parent_id">Parent Menu</label>
<select class="form-control rest" name="parent_id" id="parent_id">
<option value="0">select Menu</option>
<option value="1">one</option>
<option value="2">Two</option>
</select>
</div>
【问题讨论】:
标签: javascript jquery laravel-6