Cakephp 2 检索条件取决于子表的数据

Question

我有一个奇怪的行为，我的 cakephp 2 无法理解。 在我的模型“研究”中，我有很多关系：

class Study extends AppModel {

public $hasOne = array(
    'SubjectFilter' => array(
        'className' => 'Subject_filter',
        'dependent' => true
    )

    );


public $hasMany = array(

    'ExecutedStudyTable' => array(
            'className' => 'ExecutedStudyTable',
            'foreignKey' =>'study_id',
            'dependent' => true,
    ),   

);

ExecutedtStudyTable 模型如下所示：

class ExecutedStudyTable extends AppModel {

    public $belongsTo= array(
    'Study' => array(
        'className' => 'Study',
        'foreignKey' => 'study_id'
    ),
    'User' => array(
        'className' => 'User',
        'foreignKey' => false,
        'conditions' => array('ExecutedStudyTable.user_id = User.id')
    )

);

} 检索数据时，一切看起来都很好，直到我尝试这样做：

        $studies = $this -> Study -> find('all',array(
 'conditions' => array(
            'Study.user_id' => $cId,
            'OR'=>array(
                array('Study.state'=>'active'),
                array('Study.state'=>'rehearsal')
            ),                
            'SubjectFilter.studyCode'=>null,
            'ExecutedStudyTable.user_id'=>$user
 )
    ));

我收到此错误：Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'ExecutedStudyTable.user_id' in 'where clause'

Cakephp 像这样构建这个查询：

 SELECT `Study`.`id`, `Study`.`user_id`, `Study`.`created`, `Study`.`modified`, `Study`.`started`, `Study`.`completed`, `Study`.`title`, `Study`.`description`, `Study`.`numberParticipants`, `Study`.`state`, `User`.`id`, `User`.`username`, `User`.`password`, `User`.`role`, `User`.`firstName`, `User`.`familyName`, `User`.`email`, `User`.`addressStreet`, `User`.`addressCity`, `User`.`addressZip`, `User`.`phone1`, `User`.`phone2`, `User`.`created`, `User`.`modified`, `User`.`passwordResetCode`, `User`.`passwordResetDate`, `User`.`sendUsernameDate`, `SubjectFilter`.`id`, `SubjectFilter`.`study_id`, `SubjectFilter`.`m`, `SubjectFilter`.`f`, `SubjectFilter`.`age18_24`, `SubjectFilter`.`age25_34`, `SubjectFilter`.`age35_44`, `SubjectFilter`.`age45_54`, `SubjectFilter`.`age55plus`, `SubjectFilter`.`studyCode` FROM `eyevido`.`studies` AS `Study` LEFT JOIN `eyevido`.`users` AS `User` ON (`Study`.`user_id` = `User`.`id`) LEFT JOIN `eyevido`.`subject_filters` AS `SubjectFilter` ON (`SubjectFilter`.`study_id` = `Study`.`id`) WHERE `Study`.`user_id` = 1402402538 AND ((`Study`.`state` = 'active') OR (`Study`.`state` = 'rehearsal')) AND `SubjectFilter`.`studyCode` IS NULL AND `ExecutedStudyTable`.`user_id` = 1130451831

ExecutedStudyTable 不像 SubjectFilter 那样连接，也没有为表定义别名。为什么这在 hasOne 关系上正常工作，而不是在 hasMany 上？我在哪里犯错了？

感谢您的回复

Answer 1

如果您想通过关联模型的字段过滤模型，一种方法是通过Joining tables。

注意：为模型 ExecutedStudyTable 提及正确的表名。还要提到两个表之间的连接条件。

$studies = $this->Study->find('all',array(
 'fields' => array('Study.*'),
 'joins' => array(
      array('table' => 'executed_study_table', // Table name
        'alias' => 'ExecutedStudyTable',
        'type' => 'INNER',
        'conditions' => array(
            'ExecutedStudyTable.<field name> = Study.<field>', // Mention join condition here
        )
    )
 ),
 'conditions' => array(
        'Study.user_id' => $cId,
        'OR'=>array(
            array('Study.state'=>'active'),
            array('Study.state'=>'rehearsal')
        ),                
        'SubjectFilter.studyCode'    => null,
        'ExecutedStudyTable.user_id' => $user
  ),
  'recursive' => -1
));