如何将代码从控制器分离到存储库和工厂 [关闭]答案

【问题标题】：How separate code from controller to Repository & Factory [closed]如何将代码从控制器分离到存储库和工厂 [关闭]
【发布时间】：2021-10-10 10:32:38
【问题描述】：

我正在学习 symfony 5。我有一个控制器，但我想将逻辑分解为工厂和存储库。我在使用 FormBuilder 时遇到了一个小问题。如果工厂中没有 Formbuilder，它会通过 Request，在这种情况下是通过 Form。这个解决方案确实适用于 Form，但我做得对吗？

带有请求的TestFactory.php

class TestFactory
{   
    public function create(Request $request)
    {
        $test = new Test();
        $test->setTest1($request->get('test1');
        $test->setTest2($request->get('test2');
        return $test;
    }
}

TestController.php

class TestController extends AbstractController
{
    public function test(Request $request, TestFactory $factory, TestRepository $repository):Response
    {
        $form = $this->createForm(TestType::class);
        $form->handleRequest($request);
        
        if ($form->isSubmitted()) {
            $test = $factory->create($form);
            $repository->save($test);
        }
        return $this->render('test.html.twig', [
            'form' => $form->createView()
        ]);
    }
}

TestFactory.php

class TestFactory
{   
    public function create(Form $form)
    {
        $test = new Test();
        $test->setTest1($form->get('test1')->getData());
        $test->setTest2($form->get('test2')->getData());
        return $test;
    }
}

TestRepository.php

class TestRepository extends ServiceEntityRepository
{
    private $entityManager;
    public function __construct(ManagerRegistry $registry, EntityManagerInterface $entityManager)
    {
        parent::__construct($registry, Test::class);
        $this->entityManager = $entityManager;
    }

    public function save(Test $test)
    {
        $this->entityManager->persist($test);
        $this->entityManager->flush();
    }
}

【问题讨论】：

标签： php symfony factory symfony5

【解决方案1】：

Symfony 表单非常适合处理所有类型的底层数据，例如实体、dto-object、数组等。

这取决于您的用例和业务逻辑以及您（或您的团队）的决定

在您的情况下，您可以使用 $form->getData() 并进一步传递其值...

最常见的方法是将您的 FormType 直接绑定到特定实体。让我们坚持将您的 TestType 作为表单，将 Test 作为您生活在 src/Entity/Test.php 中的实体

在 TestType.php 中有 configureOptions 方法


public function buildForm(FormBuilderInterface $builder, array $options){
    // Assuming you have a property named $nickname in your Test class
    $builder->add('nickname');
}

public function configureOptions(OptionsResolver $resolver)
{
    $resolver->setDefaults([
        'data_class' => Test::class, // this tells your form to bind form-fields to a specific entity
        'empty_data' => new Test(), // crete new instance, if no data was passed
    ]);
}

在你的控制器中

public function test(Request $request, TestFactory $factory, TestRepository $repository):Response
{
    $form = $this->createForm(TestType::class); // since you dont pass object of Test as a 2nd param, form will automagicaly create new instance for you.

    $form->handleRequest($request);
    // don't forget to check for validation errors    
    if ($form->isSubmitted() && $form->isValid()) {
        $test = $form->getData(); // hier you'll get an instance of Test with all user input already set
        // so now you only have to save it to the database
        $repository->save($test);
        // do set succesefull flash-message ...
        // redirect to ...
    }
    return $this->render('test.html.twig', [
        'form' => $form->createView()
    ]);
}

【讨论】：