【问题标题】:Laravel - How to sum child data and pass it to parent @foreachLaravel - 如何汇总子数据并将其传递给父@foreach
【发布时间】:2020-08-13 01:53:59
【问题描述】:

我是 laravel 的新手。所以在这种情况下,我试图对子数据求和并将其传递给父索引@foreach 内的父名义列, 问题是 idk 如何在控制器中声明父 id

here's my parent index which i want to show the sum child each parent id in @foreach

here's my child index that i've already sum it, i want to show it into parent @foreach nominal column as well

这是我的 SPJCreateController,它是父控制器

class SPJCreateController extends Controller
{
   public function index(Request $request, $id)
   {
      $kegiatan = DPAKegiatan::with('dpatahun')->findorfail($id);
      $data = SPJCreate::with('spjcreatedetail')
              ->where('id_dpakegiatan', $kegiatan->id)
              ->orderBy('created_at', 'asc')
              ->paginate(10);
      $total = SPJCreateDetail::where('id_spj', $request->id)->sum('nominal');
      return view('spj.kegiatan.create.data', compact('kegiatan','data','total'));
   }
}

在这个控制器中,我声明了变量 $total,它将对 SPJCreateDetail 模型中的“名义”列求和,但我不知道如何在其中声明 where,因为 $id 是祖父母的身份证

如果我将 $request->id 放在 where

内,它会在名义列内返回 0

但是当我像这样手动调用它时它显示出来

$total = SPJCreateDetail::where('id_spj', 6)->sum('nominal');

my parent index after i put where id manually

但我不希望这样,因为我希望动态调用我的 id 并对它的每一行求和

我的 SPJCreate 模型是父模型

class SPJCreate extends Model
{
    protected $primaryKey = 'id';
    protected $table = 'spj';
    protected $fillable = ['id_dpakegiatan','tipebelanja','tipebelanjadetail'];

    public function dpakegiatan()
    {
          return $this->belongsTo(DPAKegiatan::class, 'id_dpakegiatan');
    }

    public function spjcreatedetail()
    {
          return $this->hasMany(DPAKegiatan::class, 'id');
    }
}

我的 SPJCreateDetail 模型是子模型

class SPJCreateDetail extends Model
{
     protected $primaryKey = 'id';
     protected $table = 'spj_detail';
     protected $fillable = ['id_spj','id_listbelanja','ket','penerima','nominal','ppn','pph21','pph22','pph23'];

     public function spjcreate()
     {
          return $this->belongsTo(SPJCreate::class, 'id_spj');
     }
}

对不起,我的英语不好,我希望你们能帮助我,因为我坚持了一个月试图弄清楚:(,谢谢。

我在我的控制器中 dd

$total = dd(SPJCreateDetail::where('id_spj', $request->id)->sum('nominal'));

它像这样返回 image

然而

$total = dd(SPJCreateDetail::where('id_spj', 6)->sum('nominal'));

它正确返回值 image

这是我的网络路线

    // --Here's my grandparent routes-- //
Route::get('/spj/kegiatan&id={spjkeg}', 'SPJKegController@index')->name('spjkeg')->middleware('auth');
    // ------------- //
        
    // --Here's my Parent Route Which is Gonna show my child sum-- //
Route::get('/spj/kegiatan/create&id={spjcreate}', 'SPJCreateController@index')->name('spj')->middleware('auth');
Route::post('/spj/kegiatan/create/store&id={spjcreate}', 'SPJCreateController@store')->name('spj.store')->middleware('auth');
Route::post('/spj/kegiatan/create/updt&id={spjcreate}', 'SPJCreateController@update')->name('spj.update')->middleware('auth');
Route::delete('/spj/kegiatan/create/del&id={spjcreate}', 'SPJCreateController@destroy')->name('spj.destroy')->middleware('auth');
    // ------------ //
                
    // --Here's the child route-- //
Route::get('/spj/kegiatan/create/detail&id={spjdet}', 'SPJCreateDetailController@index')->name('spj.detail')->middleware('auth');
Route::post('/spj/kegiatan/create/detail/store&id={spjdet}', 'SPJCreateDetailController@store')->name('spj.detail.store')->middleware('auth');
Route::post('/spj/kegiatan/create/detail/updt&id={spjdet}', 'SPJCreateDetailController@update')->name('spj.detail.update')->middleware('auth');
Route::delete('/spj/kegiatan/create/detail/del&id={spjdet}', 'SPJCreateDetailController@destroy')->name('spj.detail.destroy')->middleware('auth');
    // ------------ //

这是我的 View.blade.php

@php $no = 0; @endphp
@forelse($data as $spj => $result)
@php $no++; @endphp
                    <tr>
                      <td class="text-center">{{ $spj + $data->firstitem() }}.</td>
                      <td class="text-center"><b>{{ $result->tipebelanjadetail }}</b></td>
                      <td class="text-center">{{ $total }}</td>
                      <td class="text-center">
                      <div class="dropdown">
                        <button data-id="{{ $result->id }}" data-idtipebelanja="{{ $result->tipebelanja }}" data-idtipebelanjadetail="{{ $result->tipebelanjadetail }}" data-toggle="modal" data-target="#editspj" class="btn btn-success btn-s" style="background-color:#138496;border-color:#138496"><i class="fad fa-pencil"></i></button>
                        <button data-id="{{ $result->id }}" data-toggle="modal" data-target="#deletespj" class="btn btn-success btn-s" style="background-color:#eb1c0f;border-color:#eb1c0f"><i class="fad fa-trash"></i></button>
                        <button type="button" data-toggle="dropdown" class="btn btn-warning dropdown dropdown-toggle" aria-haspopup="true" aria-expanded="false"><i class="fad fa-info"></i></button>
                        <div class="dropdown-menu">
                                <a class="dropdown-item" href="{{ Route('spj.detail', $result->id)}}"><i style="padding-right:5px" class="fad fa-eye"></i>Detail</a>
                        </div>
                      </div>
                      </td>
                    </tr>
                      @empty
                      <tr>
                        <td colspan="7" class="text-center">Tidak ada data <i class="far fa-frown fa-5"></i></td>
                      </tr>
@endforelse

【问题讨论】:

  • @AndySong 我用我的 dd 编辑帖子,在那里你可以检查它:) 我错了 id 8 它是 id 6 因为 id 8 内没有数据
  • @AndySong 如果我只做了 dd($request->id) 它返回 null,代码是这样的吗? $total = dd(SPJCreateDetail::where('id_spj', $request-&gt;id)-&gt;sum('nominal')); dd($request-&gt;id)
  • @AndySong 我用网络路由更新了我的帖子

标签: php laravel sum laravel-5.8 laravel-relations


【解决方案1】:

试试这个。

   public function index($spjcreate)
   {
      $kegiatan = DPAKegiatan::with('dpatahun')->findorfail($spjcreate);
      $data = SPJCreate::with('spjcreatedetail')
              ->where('id_dpakegiatan', $kegiatan->id)
              ->withCount(['spjcreatedetail AS total' => function ($query) {
                  $query->select(DB::raw('SUM(nominal) as total'));
              }])
              ->orderBy('created_at', 'asc')
              ->paginate(10);

      return view('spj.kegiatan.create.data', compact('kegiatan','data'));
   }
@php $no = 0; @endphp
@forelse($data as $spj => $result)
@php $no++; @endphp
                    <tr>
                      <td class="text-center">{{ $spj + $data->firstitem() }}.</td>
                      <td class="text-center"><b>{{ $result->tipebelanjadetail }}</b></td>
                      <td class="text-center">{{ $result->total }}</td>
                      <td class="text-center">
                      <div class="dropdown">
                        <button data-id="{{ $result->id }}" data-idtipebelanja="{{ $result->tipebelanja }}" data-idtipebelanjadetail="{{ $result->tipebelanjadetail }}" data-toggle="modal" data-target="#editspj" class="btn btn-success btn-s" style="background-color:#138496;border-color:#138496"><i class="fad fa-pencil"></i></button>
                        <button data-id="{{ $result->id }}" data-toggle="modal" data-target="#deletespj" class="btn btn-success btn-s" style="background-color:#eb1c0f;border-color:#eb1c0f"><i class="fad fa-trash"></i></button>
                        <button type="button" data-toggle="dropdown" class="btn btn-warning dropdown dropdown-toggle" aria-haspopup="true" aria-expanded="false"><i class="fad fa-info"></i></button>
                        <div class="dropdown-menu">
                                <a class="dropdown-item" href="{{ Route('spj.detail', $result->id)}}"><i style="padding-right:5px" class="fad fa-eye"></i>Detail</a>
                        </div>
                      </div>
                      </td>
                    </tr>
                      @empty
                      <tr>
                        <td colspan="7" class="text-center">Tidak ada data <i class="far fa-frown fa-5"></i></td>
                      </tr>
@endforelse

【讨论】:

  • 不,它不会工作它也会返回 0,因为 $id 是需要的祖父母的 id,因为我的父母数据与该祖父母 id 相关
  • 我尝试你的代码,但显示新错误Undefined variable: id
  • 遗憾的是它仍然返回 0 和 $spjcreate 因为 id id_spj 需要与 id id_dpakegiatan 相同
  • 或者有没有办法制作其他 findorfail 方法?
  • 没有错,来自 SPJCreateDetail id_spj 的 ID 需要与 SPJCreate Model id 中的 ID 相同
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