更新 Laravel 中两个表的字段答案

【问题标题】：Update fields from two tables in Laravel更新 Laravel 中两个表的字段
【发布时间】：2019-11-19 19:05:22
【问题描述】：

我有 2 个模型：customer 和 customerName。在我的客户控制器中，我尝试创建一个从两个表中更新字段的方法。任何的想法？谢谢！

客户控制器

public function update(Request $request, Customer $customer)
{
    $customer = \App\CustomerName::where('customer_id', $customer->id)->first();  // if I remove this line I can update just "name" from first table

    $data = $request->validate([
        'name' => 'required|string',  //is in customer migration
        'first_name'=> 'required',    //is in customerName migration
        'last_name'=> 'required',     //is in customerName migration
    ]);
    $customer->update($data);

    return response($customer,200);
}

客户模型

class Customer extends Model
{
    protected $fillable = ['name'];

    public function customerName()
    {
        return $this->hasOne('App\CustomerName');
    }

}

客户名称模型

class CustomerName extends Model
{
    protected $fillable = ['first_name', 'last_name'];

    public function customer()
    {
        return $this->belongsTo('App\Customer');
    }
}

【问题讨论】：

标签： laravel eloquent laravel-6 eloquent-relationship

【解决方案1】：

假设客户总是为 CustomerName 创建记录，那么您应该使用：

$customer->update(['name' => $data['name']);
$customer->customerName->update(\Arr::only($data, ['first_name', 'last_name']));

此外，您应该像这样将其包装在数据库事务中：

\DB::transaction(function() use ($customer, $data) {
    $customer->update(['name' => $data['name']);
    $customer->customerName->update(\Arr::only($data, ['first_name', 'last_name']));
});

当然你应该删除这一行：

$customer = \App\CustomerName::where('customer_id', $customer->id)->first();  // if I remove this line I can update just "name" from first table

因为您应该已经使用Route model binding 设置了$customer 对象。

【讨论】：

【解决方案2】：

看看你的代码。您通过将它们命名为相同的东西来覆盖一些变量：

public function update(Request $request, Customer $customer)
{
    $customer = \App\CustomerName::where('customer_id', $customer->id)->first();
    ...

在$customer = \App\CustomerName... 行之前，$customer 是Customer 的一个实例。在该行之后，它是CustomerName 的一个实例，您不再有权访问Customer 实例。只需更改您的命名：

public function update(Request $request, Customer $customer)
{
    $customerName = \App\CustomerName::where('customer_id', $customer->id)->first();
    // Or, $customerName = $customer->customerName;
    // You shouldn't have to query if your relationship is defined properly.
    ...

接下来，相应地保存值：

$customer->name = $request->input("name"); // or $data["name"]
$customer->save();

$customerName->first_name = $request->input("first_name"); // or $data["first_name"]
$customerName->last_name = $request->input("last_name"); // or $data["last_name"]
$customerName->save();

相应地设置$customer 和$customerName 的值，然后在两个实例上调用save()。

【讨论】：

感谢您的宝贵时间！
没问题，乐于助人！

【解决方案3】：

您正在注入 Customer 实例，因此您不需要在函数中加载它。试试这个：

public function update(Request $request, Customer $customer)
{
    $data = $request->validate([
        'name' => 'required|string',  //is in customer migration
        'first_name'=> 'required',    //is in customerName migration
        'last_name'=> 'required',     //is in customerName migration
    ]);
    $customer->name = $data['name'];
    $customer->customerName->first_name = $data['first_name'];
    $customer->customerName->last_name = $data['last_name'];

    $customer->push(); // This saves the model AND the related models as well.
    return response($customer,200);
}

【讨论】：