【发布时间】:2018-01-04 14:37:01
【问题描述】:
假设我有一个包含对的 JSON 文件:
{
"Table":{
"fullwidth": "680",
"color": "#33d025",
"margin1": "30",
"margin2": "60",
"padding": "20"
}
}
然后,我想读取这些值并使用它们来替换 html 文件中的属性,如下所示:
<table width="{{Table.fullwidth}}" bgcolor="{{Table.color}}" style="margin: {{Table.margin1}}px {{Table.margin2}}px;">
<tr>
<td style="padding: {{Table.padding}}px;">
<img src="a.jpg">
</td>
</tr>
</table>
因此,在“temp/”路径中的 html 文件,在 gulping 之后,我在“dist/”中获得了一个有效的 html 文件,其属性更改如下:
<table width="680" bgcolor="#33d025" style="margin: 30px 60px;">
<tr>
<td style="padding: 20px;">
<img src="a.jpg">
</td>
</tr>
</table>
我已经尝试过 gulp-token-replace 但运行一次后,如果我在 json 文件中保存新值,它将无法再次工作,即使它触发了 watch 功能,迫使我重新启动“gulp” .
是否有一个 gulp 插件可以做到这一点?还是可以替代 gulp-token-replace 的技术?
也许只是 javascript,但是,我可以从 gulp 进程中运行类似的东西(运行手表来刷新它)吗?
Gulpfile.js 按要求:
// Include gulp
var gulp = require('gulp'),
// Include plugins
fileinclude = require('gulp-file-include'),
rename = require('gulp-rename'),
images = require('gulp-imagemin'),
cache = require('gulp-cache'),
browserSync = require('browser-sync').create(),
reload = browserSync.reload,
runSequence = require('run-sequence'),
del = require('del'),
notify = require('gulp-notify'),
gtr = require('gulp-token-replace')
// Default Task
gulp.task('default', function (cb) {
runSequence('clean', ['AA', 'BB', 'CC', 'watch'], cb);
});
// TASKS
// Clean 'dist'
gulp.task('clean', function () {
return del(['HTMLTemplates/*.html', 'HTMLTemplates/img', 'Temp/*.html']);
});
// Compress images
gulp.task('BB', function () {
gulp.src('templates/img/*.{gif,jpg,png}')
.pipe(cache(images({
optimizationLevel: 4,
progressive: true,
interlaced: true
})))
.pipe(gulp.dest('Templates/img/'));
});
// Reload browser
gulp.task('reload', function () {
browserSync.reload();
});
// Prepare Browser-sync
gulp.task('CC', ['AA'], function () {
browserSync.init({
// browserSync.init(['templates/*/*.html'], {
//proxy: 'your_dev_site.url'
server: {
baseDir: './HTMLTemplates'
}
});
});
// MAIN TASKS
gulp.task('AA', function (cbk) {
runSequence('fileinclude', 'trp', cbk);
});
// Force to run fileinclude first before replacing the tokens
gulp.task('trp', ['fileinclude'], function (done) {
function onFinish(event) {
if (event.task === 'tokenreplace') {
gulp.removeListener('task_stop', onFinish);
done();
}
}
gulp.on('task_stop', onFinish);
gulp.start('tokenreplace');
});
// Include partial files into email template (fileinclude)
gulp.task('fileinclude', function () {
// grab 'template'
return gulp.src('templates/layouts/*.tpl.html')
// include partials
.pipe(fileinclude({
basepath: 'templates/components/'
}))
// remove .tpl.html extension name
.pipe(rename({
extname: ""
}))
// add new extension name
.pipe(rename({
extname: ".html"
}))
// move file to folder
.pipe(gulp.dest('Temp/'))
.pipe(notify({
message: 'Template file includes complete'
}));
});
// Replace tokens in the index.html created by fileinclude
gulp.task('tokenreplace', ['fileinclude'], function (doit) {
var config = require('./templates/components/000 vars/config.json');
return gulp.src('Temp/index.html')
.pipe(gtr({
global: config
}))
.pipe(gulp.dest('HTMLTemplates/'))
// notify to say the task has complete
.pipe(browserSync.stream())
.pipe(notify({
message: 'Vars includes complete'
})), doit();
});
// END of MAIN TASKS
// WATCH
// Watch files for changes in html/css/tpl.html/images
gulp.task('watch', function () {
gulp.watch(['templates/components/**/*.html'], ['AA']);
gulp.watch(['templates/components/**/*.css'], ['AA']);
gulp.watch(['templates/layouts/*.tpl.html'], ['AA']);
gulp.watch(['templates/components/000 vars/*.json'], ['trp']);
gulp.watch(['HTMLTemplates/*.html'], ['reload']);
gulp.watch('templates/img/*', ['BB']);
});
【问题讨论】:
-
该注释只是表明您不能使用正则表达式来查找要替换的值。一些插件可以使用正则表达式。所以这不是你的问题。我们还需要查看您的 gulpfile.js 以提供帮助。我看不出为什么 gulp-token-replace 不能用于有观察者的任务中。
-
@mark Gulp-token-replace 有效,问题是在第一次运行后(使用一组变量读取 config.json 文件)它不会重新加载 config.json 文件。因此,整个过程被触发,但变量保持不变。我将添加 gulpfile.js 以便更清晰。
标签: javascript json gulp gulp-watch gulp-cheerio