创建容器模块 - 从 'y' 导出 * 作为 x

Question

我在一个模块中有这个：

export const Category = require('./category');
export const Roles = require('./roles');
export const FunctionalTeams = require('./functional-team');
export const WorkSteams = require('./workstream');

我尝试将其更改为 TS 导入：

export * as Category from './category';
export * as Roles from './roles';
export * as FunctionalTeams from './functional-team';
export * as WorkSteams from'./workstream';

但这不起作用，tsc 甚至无法识别该语法，我看到这些错误：

models/enums/index.ts(17,22): error TS1005: ';' expected.
models/enums/index.ts(17,27): error TS1005: ';' expected.
models/enums/index.ts(18,10): error TS1005: 'from' expected.
models/enums/index.ts(18,13): error TS1005: ';' expected.
models/enums/index.ts(18,19): error TS1005: ';' expected.

Answer 1

您可以从以下模块中导出所有元素（不允许重命名）：

export * from '../file.ts';

或者您可以导出特定元素并根据需要重命名它们：

export {Class1, Class2 as Class3} from '../file.ts';

再出口文件：https://www.typescriptlang.org/docs/handbook/modules.html