【发布时间】:2018-02-13 21:08:07
【问题描述】:
我使用这个命令:
tsc --out foo.js values/java-junit/*.ts --module amd
或
tsc --out foo.js values/java-junit/*.ts --module system
我明白了
define("index", ["require", "exports"], function (require, exports) {
"use strict";
exports.__esModule = true;
var CodeGenerator = /** @class */ (function () {
function CodeGenerator() {
this.rawCode = '';
this.styledCode = '';
}
// ...
CodeGenerator.pluginName = 'java-junit';
return CodeGenerator;
}());
exports.CodeGenerator = CodeGenerator;
});
或
System.register("index", [], function (exports_1, context_1) {
"use strict";
var __moduleName = context_1 && context_1.id;
var CodeGenerator;
return {
setters: [],
execute: function () {
CodeGenerator = /** @class */ (function () {
function CodeGenerator() {
this.rawCode = '';
this.styledCode = '';
}
// ...
CodeGenerator.pluginName = 'java-junit';
return CodeGenerator;
}());
exports_1("CodeGenerator", CodeGenerator);
}
};
});
我的问题是 - 有没有办法用命令行选项来命名模块,而不是模块名称是“索引”?
【问题讨论】:
标签: typescript typescript2.0 tsc