【发布时间】:2011-08-23 06:09:15
【问题描述】:
我查看了struts2.0的tile示例,发现在tiles.xml中jsp页面的调用如下:
<definition name="welcome" extends="baseLayout">
<put-attribute name="title" value="Welcome"/>
<put-attribute name="body" value="/welcome.jsp"/>
但我的问题是,如果我想调用动作类而不是 .jsp 页面而不是如何调用它
<definition name="friends" extends="baseLayout">
<put-attribute name="title" value="Friends"/>
<put-attribute name="body" value="/checkActionLink.action"/>
当我尝试编写执行上述代码时,它显示的错误是 checkActionLink.action 未找到......提前感谢您的帮助......
下面是web.xml文件
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Struts2Example15</display-name>
<servlet>
<servlet-name>tiles</servlet-name>
<servlet-class>org.apache.tiles.web.startup.TilesServlet</servlet-class>
<init-param>
<param-name>org.apache.tiles.impl.BasicTilesContainer.DEFINITIONS_CONFIG</param-name>
<param-value>/WEB-INF/tiles.xml</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<listener>
<listener-class>org.apache.struts2.tiles.StrutsTilesListener</listener-class>
</listener>
<filter>
<filter-name>struts2</filter-name>
<filter-class>
org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
<dispatcher>REQUEST</dispatcher>
<dispatcher>FORWARD</dispatcher>
<dispatcher>INCLUDE</dispatcher>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
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