【发布时间】:2020-04-16 00:44:44
【问题描述】:
使用: "@react-navigation/drawer": "^5.4.0", "@react-navigation/native": "^5.1.4",
App.js:
import { createDrawerNavigator } from '@react-navigation/drawer';
...
const Drawer = createDrawerNavigator();
const DrawerRender = () => {
return (
<NavigationContainer>
<Drawer.Navigator drawerContent={props => <DrawerContent {...props} />}>
<Drawer.Screen name="Home" component={Home} />
<Drawer.Screen name="Screen1" component={Screen1} options={{unmountOnBlur: true, gestureEnabled: false}} />
<Drawer.Screen name="Screen2" component={Screen2} options={{unmountOnBlur: true, gestureEnabled: false}} />
</Drawer.Navigator>
</NavigationContainer>
);}
从屏幕 1:
navigateToPage = page_id => {
this.closeCommentScreen();
this.reopenModal = true;
this.props.navigation.navigate('Screen2', {'page_id': 'testing'});
}
在屏幕 2 上:
export default class Screen2 extends React.Component {
constructor(props) {
super(props);
}
componentDidMount() {
let id = this.props.navigation.state.params.page_id
...
我尝试打印“this.props.navigation”,它总是返回空字典 {},因此参数未定义。
我做错了什么?
【问题讨论】:
-
看起来像this
-
我的 this.props.navigation 是空的。 state.params 将始终为空
-
两个屏幕都不能用?
-
navigation.navigate 可以正常工作。当我尝试从 Screen2 访问参数时,它会出错
标签: react-native react-native-android react-navigation react-native-ios