从 LDAP/Active Directory 搜索结果中读取属性的最快方法答案

【问题标题】：Fastest way of reading a property from LDAP/Active Directory Search results从 LDAP/Active Directory 搜索结果中读取属性的最快方法
【发布时间】：2014-03-27 09:00:13
【问题描述】：

using (DirectoryEntry rootEntry = new DirectoryEntry(ConfigurationKeys.Ldap, string.Empty, string.Empty, AuthenticationTypes.None))
{
    using (DirectorySearcher adSearch = new DirectorySearcher(rootEntry))
    {
        adSearch.SearchScope = SearchScope.Subtree;
        adSearch.PropertiesToLoad.Add("givenname");
        adSearch.PropertiesToLoad.Add("mail");

        adSearch.Filter = "(mail=myemail@mydomain.org)";
        SearchResult adSearchResult = adSearch.FindOne();
    }
}

从上面的示例中，检索属性“givenname”并将其存储到字符串变量中的最有效方法是什么？

【问题讨论】：

标签： c# c#-4.0 active-directory ldap

【解决方案1】：

由于您在搜索中加载了属性列表中的属性，因此只需在搜索结果中访问该属性：

using (DirectoryEntry rootEntry = new DirectoryEntry(ConfigurationKeys.Ldap, string.Empty, string.Empty, AuthenticationTypes.None))
{
    using (DirectorySearcher adSearch = new DirectorySearcher(rootEntry))
    {
        adSearch.SearchScope = SearchScope.Subtree;
        adSearch.PropertiesToLoad.Add("givenname");
        adSearch.PropertiesToLoad.Add("mail");

        adSearch.Filter = "(mail=myemail@mydomain.org)";

        SearchResult adSearchResult = adSearch.FindOne();

        // make sure the adSearchResult is not null
        // and the "givenName" property is not null (could be empty / null)
        if(adSearchResult != null && adSearchResult.Properties["givenName"] != null) 
        {
            // make sure the givenName property contains at least one string value
            if (adSearchResult.Properties["givenName"].Count > 0)
            {
               string givenName = adSearchResult.Properties["givenName"][0].ToString();
            }
        }
    }
}

【讨论】：