【发布时间】:2015-04-10 05:13:16
【问题描述】:
基本上,我想编写一个返回闭包的函数。我怎样才能做到这一点而不必返回Box<FnOnce(u32)>?
从closures chapter of the rust book 中,我读到闭包只是结构的语法糖和FnOnce 的实现。这是我的尝试:
#[derive(Debug)]
struct MyError {
code: u32,
location: &'static str,
}
// Here is my closure:
struct MyErrorPartial {
location: &'static str,
}
impl FnOnce(u32) for MyErrorPartial {
type Output = MyError;
fn call_once(self, args: u32) -> MyError {
MyError {
code: args,
location: self.location,
}
}
}
fn error_at(location: &'static str) -> MyErrorPartial {
MyErrorPartial {location: location}
}
fn function_returning_code() -> Result<(), u32> {
Err(123)
}
fn function_with_error() -> Result<(), MyError> {
try!(function_returning_code().map_err(error_at("line1")));
try!(function_returning_code().map_err(error_at("line2")));
Ok(())
}
fn main() {
function_with_error().unwrap();
}
目前报错:
<anon>:11:12: 11:17 error: associated type bindings are not allowed here [E0229]
<anon>:11 impl FnOnce(u32) for MyErrorPartial {
^~~~~
【问题讨论】:
标签: rust higher-order-functions