无法从异步存储中检索密钥反应本机

Question

我正在尝试使用记住我切换开关来存储具有异步存储的用户电子邮件。我不确定为什么要通过 getRememberedUser 调用检索“null”？我究竟做错了什么？这是 React Native ，我也有一个 redux 商店（这里没有真正使用），但不确定这是否重要。谢谢！

  const [userEmail, setuserEmail] = useState("");
  const [rememberMe, setrememberMe] = useState(false);

const rememberUser = async () => {
    try {
      await AsyncStorage.setItem("userEmail", userEmail);
      console.log("stored");
    } catch (error) {
      // Error saving data
    }
  };

  const forgetUser = async () => {
    try {
      await AsyncStorage.removeItem("userEmail");
      console.log("forgotten");
    } catch (error) {
      // Error removing
    }
  };

  const getRememberedUser = async () => {
    try {
      const value = await AsyncStorage.getItem("userEmail");
       console.log(value)
      if (value !== null) {
        // We have username!!
        setuserEmail(value);
      }
    } catch (error) {
      // Error retrieving data
    }
  };

          <Input
          id="email"
          label="E-Mail"
          keyboardType="email-address"
          required
          email
          autoCapitalize="none"
          errorText="Please enter a valid email address."
          onInputChange={inputChangeHandler}
          initialValue={userEmail}
        />
          <Switch
            value={rememberMe}
            onValueChange={(value) => toggleRememberMe(value)}
          />
          <Text>Remember Me</Text>
          <Button
            title="get uersname"
            onPress={() => {
              getRememberedUser();
            }}
          ></Button>

Answer 1

保存时需要字符串化，

await AsyncStorage.setItem("userEmail", JSON.stringify(userEmail));

检索时解析

const value = await AsyncStorage.getItem("userEmail");
const userEmail = JSON.parse(value);