【发布时间】:2020-04-16 16:32:28
【问题描述】:
我需要在“takeUntil”工作时执行最后一个操作,然后进一步发送该数据,但我无法确切知道 takeUntil 何时完成工作。 谢谢大家。
ngOnInit(): void {
const thumb = document.getElementById("thumb");
const track: HTMLElement = document.getElementById("track");
const activeTrack = document.getElementById("active-track");
const mouseUp = fromEvent(document, "mouseup");
const mouseMove = fromEvent(document, "mousemove").pipe(
map((item) => this.mouseEventToCoordinate(item, track))
);
const activeTrackClick = fromEvent(activeTrack, "click").pipe(
map((item) => this.mouseEventToCoordinate(item, track))
);
const trackClick = fromEvent(track, "click").pipe(
map((item) => this.mouseEventToCoordinate(item, track))
);
const mouseDown = fromEvent(thumb, "mousedown");
mouseDown
.pipe(
switchMap(() => mouseMove),
merge(trackClick, activeTrackClick),
takeUntil(mouseUp),
repeat()
)
.subscribe((item: { trackWidth: number; position: number }) => {
const newX = (item.position / item.trackWidth) * 100;
activeTrack.style.width = (newX + 1).toString() + "%";
thumb.style.left = newX.toString() + "%";
if (item === "Done") {
// Do somethings
}
});
}
【问题讨论】:
-
所以基本上你需要在 mouseup 上做点什么?
标签: angular rxjs reactive-programming