【问题标题】:Realm Android parsing issueRealm Android解析问题
【发布时间】:2016-02-10 07:42:54
【问题描述】:

我正在尝试使用 Android 中的领域数据库解析和插入 JSON 响应。以下是我最终得到的例外:

io.realm.exceptions.RealmException: Could not create JSON array from string
at io.realm.Realm.createOrUpdateAllFromJson(Realm.java:396)
at mobile.login.LoginFragment$1.onResponse(LoginFragment.java:218)
at okhttp3.RealCall$AsyncCall.execute(RealCall.java:133)
at okhttp3.internal.NamedRunnable.run(NamedRunnable.java:32)                                                                                atjava.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)

我正在尝试解析的 JSON:

{
  "count": 1,
  "statuses": [
    {
      "id": 0,
      "name": "Visible",
      "count": 0,
      "sort_order": 0
    },
    {
      "id": "1",
      "name": "Invisible",
      "count": 0,
      "sort_order": "1"
    }]
}

Count.java Pojo

public class Count extends RealmObject{

    @PrimaryKey
    private int count;

    private RealmList<Statuses> statuses;

    public int getCount() {
        return count;
    }
    public void setCount(int count) {
        this.count = count;
    }
    public RealmList<Statuses> getStatuses() {
        return statuses;
    }
    public void setStatuses(RealmList<Statuses> statuses) {
        this.statuses = statuses;
    }
}

Statuses.java Pojo

public class Statuses extends RealmObject{
    @PrimaryKey
    @SerializedName("id")
    @Expose
    private String id;
    @SerializedName("name")
    @Expose
    private String name;
    @SerializedName("count")
    @Expose
    private Integer count;
    @SerializedName("sort_order")
    @Expose
    private String sortOrder;

    public String getId() {
        return id;
    }
    public void setId(String id) {
        this.id = id;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public Integer getCount() {
        return count;
    }
    public void setCount(Integer count) {
        this.count = count;
    }
    public String getSortOrder() {
        return sortOrder;
    }
    public void setSortOrder(String sortOrder) {
        this.sortOrder = sortOrder;
    }
}

这就是我尝试解析和存储 JSON 的方式:

Realm realm = Realm.getInstance(getContext());
realm.beginTransaction();
realm.createOrUpdateAllFromJson(Order.class, **"JSON STRING HERE"**);
realm.commitTransaction();

如果有人能帮我解决这个问题,那真是太棒了。提前致谢!

【问题讨论】:

标签: android realm realm-list


【解决方案1】:

方法createOrUpdateAllFromJson() 期望您在json 中的根对象是Array

您的代码适用于这个 json:

[{
  "count": 1,
  "statuses": [
    {
      "id": 0,
      "name": "Visible",
      "count": 0,
      "sort_order": 0
    },
    {
      "id": "1",
      "name": "Invisible",
      "count": 0,
      "sort_order": "1"
    }]
}]

使用createOrUpdateObjectFromJson() 仅添加一个对象(感谢@EpicPandaForce)。


这里是createOrUpdateAllFromJson方法的源码

/**
 * Tries to update a list of existing objects identified by their primary key with new JSON data. If an existing
 * object could not be found in the Realm, a new object will be created. This must happen within a transaction.
 *
 * @param clazz type of {@link io.realm.RealmObject} to create or update. It must have a primary key defined.
 * @param json string with an array of JSON objects.
 * @throws java.lang.IllegalArgumentException if trying to update a class without a
 * {@link io.realm.annotations.PrimaryKey}.
 * @throws RealmException if unable to create a JSON array from the json string.
 * @see #createAllFromJson(Class, String)
 */
public <E extends RealmObject> void createOrUpdateAllFromJson(Class<E> clazz, String json) {
    if (clazz == null || json == null || json.length() == 0) {
        return;
    }
    checkHasPrimaryKey(clazz);

    JSONArray arr;
    try {
        arr = new JSONArray(json);
    } catch (JSONException e) {
        throw new RealmException("Could not create JSON array from string", e);
    }

    createOrUpdateAllFromJson(clazz, arr);
}

【讨论】:

  • 这也意味着他应该尝试createOrUpdateFromJson(),它不需要数组而是单个对象。
  • @llya Tretyakov : 你会推荐我作为解决方案,因为我的服务器响应是我无法改变的。
  • @HareshChaudhary 看看这个方法createOrUpdateObjectFromJson()。可用于添加一个对象(不是数组)
  • @llya:我是否应该将返回的具有 JSON 数组的字符串转换为 JSON 对象,然后在传递详细信息之前手动将该 JSON 对象重新转换为字符串?
  • 非常感谢@IIya 的想法,我不得不手动添加这两个括号才能解决这个问题,是的,你的回答是正确的!
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