如何将参数传递到 StackNavigator 中的屏幕？

Question

我的 React Native 代码：

import React, { Component } from 'react';
import { AppRegistry, ActivityIndicator, StyleSheet, ListView, 
  Text, Button, TouchableHighlight, View } from 'react-native';

import { StackNavigator } from 'react-navigation';
import DetailsPage from './src/screens/DetailsPage';

class HomeScreen extends React.Component {

   constructor() {
    super();
    const ds = new ListView.DataSource({rowHasChanged: (r1, r2) => r1 !== r2});
    this.state = {
      userDataSource: ds,
    };
  }

  componentDidMount(){
      this.fetchUsers();
  }

    fetchUsers(){

        fetch('https://jsonplaceholder.typicode.com/users')
            .then((response) => response.json())
            .then((response) => {
                this.setState({
                    userDataSource: this.state.userDataSource.cloneWithRows(response)
                });
            });
    }

    onPress(user){
        this.props.navigator.push({
            id: 'DetailPage'
        });
    }

  renderRow(user, sectionID, rowID, highlightRow){
      return(
      <TouchableHighlight onPress={()=>{this.onPress(user)} } >
      <View style={styles.row}>
        <Text style={styles.rowText}> {user.name} </Text>

      </View>
      </TouchableHighlight>
      )
  }


  render(){
      return(
          <ListView
            dataSource = {this.state.userDataSource}
            renderRow = {this.renderRow.bind(this)}
          />
      )
  } 
}

导航配置：

const NavigationTest = StackNavigator({
  Home: { screen: HomeScreen },
  DetailsPage: { screen: DetailsPage },
});

详细信息屏幕是：

import React, { Component } from 'react';
import { StyleSheet, Text, View } from 'react-native';

import styles from '../styles';


export default class DetailsPage extends React.Component {
  static navigationOptions = ({ navigation }) => ({
    title: `User: ${navigation.state.params.user.name}`,
  });
  render() {
    const { params } = this.props.navigation.state;
    return (
      <View>
        <Text style={styles.myStyle}>Name: {params.name}</Text>
        <Text style={styles.myStyle}>Email: {params.email}</Text>
      </View>
    );
  }
}

我无法使用代码将user 传递给DetailsPage：

onPress(user){
        this.props.navigator.push({
            id: 'DetailPage'
        });
    }

我想使用onPress 函数导航到DetailPage。如果我像这样提醒它：

onPress(user){ Alert.alert(user.name)}

我确实得到了值，但是如何将它传递到其他页面？

非常感谢！

Answer 1

您可以使用navigate 函数的第二个参数传递参数：

onPress(user) {
  this.props.navigation.navigate(
    'DetailPage',
    { user },
  );
}

React Navigation 5.x (2020)

通过this.props.route.params 访问它们。例如在你的DetailsPage：

<Text style={styles.myStyle}>{this.props.route.params.user.name}</Text>

https://reactnavigation.org/docs/params/

反应导航

通过this.props.navigation.state.params 访问它们。例如在你的DetailsPage:

<Text style={styles.myStyle}>{this.props.navigation.state.params.user.name}</Text>

https://reactnavigation.org/docs/4.x/params/

Answer 2

在反应钩子中，参数使用 useNavigation 发送导航

import { useNavigation } from '@react-navigation/native';

const navigation = useNavigation();

<Button
      title="Back"
      onPress={() => {
        navigation.navigate('MyScreen',{name:'test'});
      }}
    />

然后使用 useNavigationParam 访问它们

function MyScreen() {
  const name = useNavigationParam('name');
  return <p>name is {name}</p>;
}

Answer 3

See this.

它解决了我的问题。

this.props.navigation.navigate("**stack_Name**", {
 screen:"screen_name_connect_with_**stack_name**",
 params:{
 user:"anything_string_or_object"
}
})

Answer 4

在你的第一页，说国家列表

const CountriesList = ({ navigation }) => {

/* Function to navigate to 2nd screen */
  const viewCountry = (country) => {
    navigation.navigate('ListItemPageRoute', { name: country.country_name });
  };
}

对于您的第二个页面名称，请说 ListItemPageRoute

const ListItemPageRoute = (props) => {

return (
    <View style={styles.container}>
        <Text style={styles.countryText}> { props.route.params.name } </Text>
    </View>
  );
};

'Props.route' 对象将包含您希望从一个屏幕传递到另一个屏幕的所有参数的列表。

Answer 5

对我来说，通过 useNavigation() 和 useRoute() 解决了它：

对于功能组件：

import * as React from 'react';
import { Button } from 'react-native';
import { useNavigation } from '@react-navigation/native';

function MyBackButton() {
  const navigation = useNavigation();

  return (
    <Button
      title="Back"
      onPress={() => {
        navigation.goBack();
      }}
    />
  );
}

对于类组件：

class MyText extends React.Component {
  render() {
    // Get it from props
    const { route } = this.props;
  }
}

// Wrap and export
export default function(props) {
  const route = useRoute();

  return <MyText {...props} route={route} />;
}

Answer 6

onPress={() => {this.props.navigation.navigate('AllImages', {Types: item.type })} console.log('valuesstrong text', this.props.route.params.Types);**

Answer 7

1)如何通过参数将数据发送到另一个屏幕： onPress={(item) => props.navigation.navigate('Your ScreenName', {item : item})}

2)如何在另一个屏幕上获取数据： const {item} = props.route.params

Answer 8

你可以很容易地做到这一点。
您想将一些参数传递给您的屏幕吗？这样做：

export default () => {
  
  const MainScreenComponent = ({navigation}) => (
    <MainScreen
      navigation={navigation}
      /**
      *
      * And here your parameters...
      *
      */
    />
  );

  const HomeScreenComponent = ({navigation}) => (
    <HomeScreen
      navigation={navigation}
      /**
      *
      * And here your parameters...
      *
      */
    />
  );

  return (
    <NavigationContainer>
      <Stack.Navigator initialRouteName="MainScreen">
        <Stack.Screen name="MainScreen" component={MainScreenComponent}/>
        <Stack.Screen name="HomeScreen" component={MomeScreenComponent}/>
      </Stack.Navigator>
    </NavigationContainer>
  );
};