【问题标题】:Why is Dash giving a parse error when uploading files?为什么 Dash 在上传文件时会出现解析错误?
【发布时间】:2019-08-27 15:10:56
【问题描述】:

上传 Excel 或 CSV 会导致错误。我关注了 Dash 演示,但是一旦我尝试扩展它以执行诸如绘图之类的操作,它就不起作用了。我不想只展示一张桌子。 Dash_Table 函数已更新,因此之前使用 Dash_Table_Experiments 的示例不再有效

我整晚都在交换堆栈,修改我的代码并阅读其他解决方案。下面提供了完整的工作代码。我还想添加一个下拉回调函数来通过分类变量“过滤”数据。

 import base64
 import datetime
 import io
 import plotly.graph_objs as go
 import dash
 from dash.dependencies import Input, Output, State
 import dash_core_components as dcc
 import dash_html_components as html
 import dash_table

 import pandas as pd


 external_stylesheets = ['https://codepen.io/chriddyp/pen/bWLwgP.css']

 app = dash.Dash(__name__, external_stylesheets=external_stylesheets)

 app.layout = html.Div([
  dcc.Upload(
      id='upload-data',
      children=html.Div([
        'Drag and Drop or ',
        html.A('Select Files')
    ]),
    style={
        'width': '100%',
        'height': '60px',
        'lineHeight': '60px',
        'borderWidth': '1px',
        'borderStyle': 'dashed',
        'borderRadius': '5px',
        'textAlign': 'center',
        'margin': '10px'
    },
    # Allow multiple files to be uploaded
    multiple=False
  ),
  html.Div(id='output-data-upload'),
  dcc.Graph(id='graph1')
 ])


 def parse_contents(contents, filename):
   content_type, content_string = contents.split(',')

   decoded = base64.b64decode(content_string)

   try:
       if 'csv' in filename:
         # Assume that the user uploaded a CSV file
          df = pd.read_csv(
            io.StringIO(decoded.decode('utf-8')))
       elif 'xls' in filename:
          # Assume that the user uploaded an excel file
          df = pd.read_excel(io.BytesIO(decoded))
   except Exception as e:
       print(e)
       return html.Div([
           'There was an error processing this file.'
       ])

return html.Div([
    html.H5(filename),
    # html.H6(datetime.datetime.fromtimestamp(date)),

    dash_table.DataTable(
        data=df.to_dict('records'),
        columns=[{'name': i, 'id': i} for i in df.columns]
    ),

    html.Hr(),  # horizontal line
    # For debugging, display the raw contents provided by the web browser
    html.Div('Raw Content'),
    html.Pre(contents[0:200] + '...', style={
        'whiteSpace': 'pre-wrap',
        'wordBreak': 'break-all'
    })
 ])


 @app.callback(Output('output-data-upload', 'children'),
          [Input('upload-data', 'contents')],
          [State('upload-data', 'filename')])
 def update_output(list_of_contents, list_of_names):
   if list_of_contents is not None:
       children = [
           parse_contents(c, n) for c, n in
           zip(list_of_contents, list_of_names)]
      return children

@app.callback(
   Output('graph1', 'figure'),
   [Input('upload-data', 'contents'),
   Input('upload-data', 'filename')])

def plot_graph(contents, filename):
   df = parse_contents(contents, filename)
   trace1 = go.Bar(
        x=df['Quarter'],
        y=df['Score'],
    )

layout = go.Layout(
    title='graph1'

)
fig = go.Figure(data = [trace1], layout=layout)
return fig

if __name__ == '__main__':
   app.run_server(debug=True)

我得到的错误是:回调错误更新 output-data-upload.children: ValueError: not enough values to unpack (expected 2, got 1)

AttributeError: 'NoneType' 对象没有属性 'split'

问题似乎在于 python 如何处理解析器:

  def parse_contents(contents, filename):
     content_type, content_string = contents.split(',')

   decoded = base64.b64decode(content_string)

但似乎没有任何解决方案可以解决问题。

请帮忙。由于很多人都在为此苦苦挣扎(看起来),如果我们能够解决它并发布一个功能代码(Github?)来完成 Shiny 已经可以轻松完成的事情,那就太好了。

【问题讨论】:

    标签: python plotly plotly-dash


    【解决方案1】:

    您的代码:

       children = [
           parse_contents(c, n) for c, n in
           zip(list_of_contents, list_of_names)]
    

    然后

    def parse_contents(contents, filename):
        content_type, content_string = contents.split(',')
        decoded = base64.b64decode(content_string)
        ...
    

    这里错误发生在c为None时,那么parse_contentscontents参数为None,就会出现“None has no .split”错误。

    如果c 不是 None 而是只有一个词,则contents.split() 只返回一个元素,并出现“没有足够的值来解包”错误。

    我会过滤它:

    pairs = zip(list_of_contents, list_of_names)
    children = [parse_contents(c, n) for (c, n) in pairs if c and (len(c.split(',')) == 2)]
    

    您也可以考虑在parse_contents 之外进行拆分并更改其周围的代码。

    我也会尝试记录内容错误的文件名,例如[n for (c, n) in pairs if not c or len(c.split(',')) != 2]).

    【讨论】:

    • 感谢您的快速回复。所以你建议:def update_output(list_of_contents, list_of_names):if list_of_contents is not None:pairs = zip(list_of_contents, list_of_names)children = [parse_contents(c, n) for c, n in pairs if c] return children
    • 因为我试过这段代码,我得到了同样的错误。
    • 我将我的答案扩展到了额外的案例。
    • 谢谢。这解决了它。但是,因此,我收到绘图回调函数的回调错误。回调不应该识别数据框对象中的列标题吗?有 3 列:“品牌”、“季度”和“分数” def plot_graph(contents, filename): df = parse_contents(contents, filename) trace1 = go.Bar( x=df['Quarter'], y= df['分数'], )
    • 可能与此错误有关:AttributeError: 'NoneType' object has no attribute 'split'
    【解决方案2】:

    解决了。在这里发帖供其他人使用:

    def parse_contents(contents, filename):
    if contents is not None:
        content_type, content_string = contents.split(',')
    
        decoded = base64.b64decode(content_string)
    
        try:
            if 'csv' in filename:
                # Assume that the user uploaded a CSV file
                df = pd.read_csv(
                    io.StringIO(decoded.decode('utf-8')))
            elif 'xlsx' in filename:
                # Assume that the user uploaded an excel file
                df = pd.read_excel(io.BytesIO(decoded))
        except Exception as e:
            print(e)
            return html.Div([
                'There was an error processing this file.'
            ])
    
        return df
    else:
        return [{}]
    
    
    @app.callback(Output('table', 'data'),
                  [Input('upload-data', 'contents'),
                  Input('upload-data', 'filename')])
    def update_output(contents, filename):
        if contents is not None:
            df = parse_contents(contents, filename)
            if df is not None:
                return df.to_dict('records')
            else:
                return [{}]
        else:
            return [{}]
    @app.callback(
        Output('graph1', 'figure'),
        [Input('upload-data', 'contents'),
         Input('upload-data', 'filename')])
    
    def plot_graph(contents, filename):
        df = parse_contents(contents, filename)
        trace1 = go.Bar(
                x=df['Quarter'],
                y=df['Score'],
            )
    
        layout = go.Layout(
            title='graph1'
    
    )
    fig = go.Figure(data = [trace1], layout=layout)
    return fig
    

    【讨论】:

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