【发布时间】:2013-08-26 15:52:46
【问题描述】:
我在第一页上有一个搜索栏,结果显示在带有分页的第二页上。问题是分页不适用于$_GET 或$_POST 变量。
我的意思是当表单提交时,第二页上的 url 更改为类似
products.php?search=something 我可以看到显示的结果。
但是,当我点击分页的下一个按钮时,我得到 undefined index search error 并且 url 更改为 products.php?page=2
那么有什么方法可以存储$_GET['search']; 值,以便在页码更改时使用它?
<form action="products.php" method="post">
<input type="text" name="search">
<input type="Submit">
</form>
products.php
<?php
/*
* Connect to the database (Replacing the XXXXXX's with the correct details)
*/
try
{
$dbh = new PDO('mysql:host=localhost;dbname=db', 'root', '');
}
catch(PDOException $e)
{
print "Error!: " . $e->getMessage() . "<br/>";
die();
}
/*
* Get and/or set the page number we are on
*/
if(isset($_GET['page']))
{
$page = $_GET['page'];
}
else
{
$page = 1;
}
/*
* Set a few of the basic options for the class, replacing the URL with your own of course
*/
$options = array(
'results_per_page' => 100,
'url' => 'products.php?page=*VAR*',
'db_handle' => $dbh
);
$q = $_GET['search'];
/*
* Create the pagination object
*/
try
{
$paginate = new pagination($page, "SELECT * FROM products where title LIKE '%$q%' order by id desc", $options);}
catch(paginationException $e)
{
echo $e;
exit();
}
if($paginate->success == true)
{
$paginate_result = $paginate->resultset->fetchAll();
foreach($paginate_result as $row)
{
echo $row['title'];
}
?>
<?php echo "<li>"; //this is next and prev button for the pagination class if results exceed the limit.
echo $ball->links_html;
echo "</li>"; ?>
【问题讨论】:
标签: php mysql pdo get pagination