尝试在数据库 GET 方法上插入的 PHP 错误

Question

当我尝试在数据库中插入两个值时，我的 PHP 出现问题。

我正在使用 Android 并调用 php 进行插入。我发布了我的 Android 代码：

 private void loadPhase() {
    String url = "http://www.myurl.com/scriptsfolder/myphptoinsertranking.php?id=prueba0101&points=200";

    if (numQuestion < 11) {
        header4questions.setText(listQuestions.get(questionPosition));

        answer1.setText(listAnswers.get(questionPosition * 4));
        answer2.setText(listAnswers.get((questionPosition * 4) + 1));
        answer3.setText(listAnswers.get((questionPosition * 4) + 2));
        answer4.setText(listAnswers.get((questionPosition * 4) + 3));

        if(numQuestion % 5 == 0 && numQuestion > 0)
        {
            MediaPlayer mp = MediaPlayer.create(this, R.raw.aplausos);
            mp.start();
        }

        numQuestion++;
    }
    else {
        Toast.makeText(getApplicationContext(), "You have finished the quiz!", Toast.LENGTH_SHORT).show();

        StringRequest stringRequest = new StringRequest(Request.Method.GET, url, new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {
                        Toast.makeText(QuizActivity.this,response,Toast.LENGTH_LONG).show();

                        Intent inn1 = getIntent();
                        inn1 = new Intent(QuizActivity.this, MainActivity.class);
                        startActivity(inn1);
                    }
                },
                new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        Toast.makeText(QuizActivity.this, "INSERT ERROR", Toast.LENGTH_LONG).show();

                        Intent inn1 = getIntent();
                        inn1 = new Intent(QuizActivity.this, MainActivity.class);
                        startActivity(inn1);
                    }
                }) {

        };

        //Adding the string request to the queue
        RequestQueue requestQueue = Volley.newRequestQueue(this);
        requestQueue.add(stringRequest);
    }
} 

我还发布了我的 php 代码：

<?php
 if($_SERVER['REQUEST_METHOD']=='GET'){
$id = $_POST['id'];
$points = $_POST['points'];

$con = mysqli_connect("server.com:1111","username","userpassword","databasename");
if (!$con->connect_error) 
{
    $sql= "INSERT INTO table (IdUser, Points) values ('$id','$points')"; 

    if(mysqli_query($con,$sql)){
        echo "Successfully Registered";
    }
    else{
        echo "Could not register"; 
    }
}
else{
    echo 'error de conexion';
}
}
?>

我得到的结果是：“无法注册”。即使我尝试使用 Android 代码或转到资源管理器上的 URL。

但是，当我在 phpmyadmin 上进行插入时，我没有任何错误，并且可以正常工作。

我不知道为什么它不能插入，请任何人帮助我吗？

非常感谢！

Answer 1

您在检查 POST 时发出 GET 请求，请将 php 的代码更改为此

<?php
 if($_SERVER['REQUEST_METHOD']=='GET'){
$id = $_GET['id'];
$points = $_GET['points'];

$con = mysqli_connect("server.com:1111","username","userpassword","databasename");
if (!$con->connect_error) 
{
    $sql= "INSERT INTO table (IdUser, Points) values ('$id','$points')"; 

    if(mysqli_query($con,$sql)){
        echo "Successfully Registered";
    }
    else{
        echo "Could not register"; 
    }
}
else{
    echo 'error de conexion';
}
}
?>

Answer 2

 if($_SERVER['REQUEST_METHOD']=='GET'){  //that's get method
  $id = $_POST['id']; // here you are getting value from $_POST

应该是$_GET

Answer 3

改一下

$id = $_POST['id']; $points = $_POST['points'];

到这里，

$id = $_GET['id']; $points = $_GET['points'];