将返回的 PHP 数据转换为 JavaScript 对象

Question

我有一个数据集，它需要与 JavaScript 变量采用相同的格式，如下所示：

var theData = {
    datasets: [
        {
            label: "My First dataset",
            backgroundColor: "rgba(179,181,198,0.2)",
            borderColor: "rgba(179,181,198,1)",
            data: [65, 59, 90, 81, 56, 55, 40]
        },
        {
            label: "My Second dataset",
            backgroundColor: "rgba(255,99,132,0.2)",
            borderColor: "rgba(255,99,132,1)",
            data: [28, 48, 40, 19, 96, 27, 100]
        }
    ],
    labels: ["Eating", "Drinking", "Sleeping", "Designing", "Coding", "Cycling", "Running"]
};

数据是在 PHP 中构建的，但我无法得到它。

这是我在 PHP 中的内容（示例数据，但填充方法相同）：

$data = array();

$data['datasets'][1]['label']           = "First Data Set";
$data['datasets'][1]['borderColor']     = "rgba(30, 87, 153, .9)";
$data['datasets'][1]['backgroundColor'] = "rgba(30, 87, 153, .5)";

$data['datasets'][2]['label']           = "Afternoon";
$data['datasets'][2]['borderColor']     = "rgba(41, 137, 216, .9)";
$data['datasets'][2]['backgroundColor'] = "rgba(41, 137, 216, .5)";

// Loop through some foreachs and fill the $data
// Not the actual loop I use but same principle

foreach ($theData as $data)
{
    $data['datasets'][1]['data'][] = data;
}

foreach ($otherData as $data)
{
    $data['datasets'][2]['data'][] = data;
}

当我执行 console.log(JSON.stringify(theData)) 时，这会使用 json_encode(); 返回给 JavaScript，我得到了这个：

{
    "datasets":{
        "1":{
            "label":"Morning",
            "borderColor":"rgba(125, 185, 232, .9)",
            "backgroundColor":"rgba(125, 185, 232, .5)",
            "borderWidth":1,
            "data":[
                "24",
                0,
                0,
                "30",
                "24",
                "36",
                "36"
            ]
        },
        "2":{
            "label":"Afternoon",
            "borderColor":"rgba(41, 137, 216, .9)",
            "backgroundColor":"rgba(41, 137, 216, .5)",
            "borderWidth":1,
            "data":[
                "24",
                0,
                0,
                "24",
                "24",
                "30",
                "36"
            ]
        }
    },
    "labels":[
        "Sun Aug 14",
        "Mon Aug 15",
        "Tue Aug 16",
        "Wed Aug 17",
        "Thu Aug 18",
        "Fri Aug 19",
        "Sat Aug 20"
    ]
}

这适用于 Chart.js 2.3。顶部的示例数据直接来自 Chart.js 示例数据。上面的 JSON 是我的结果。因为它们不相同，所以图表不起作用。我可以更改我的 PHP 以使其更像最顶部的示例吗？

Answer 1

让我们从头开始

• theData 是 object
• datasets 是 array 的 objects
• labels 是 array

让我们开始构建这个

$data = array();
$data['datasets'] = array();
$data['datasets'][] = array("label" => "First Data Set",
     "borderColor" => "rgba(30, 87, 153, .9)",
     "backgroundColor" => "rgba(30, 87, 153, .5)"
     );
$data['datasets'][] = array("label" => "Second Data Set",
     "borderColor" => "rgba(41, 137, 216, .9)",
     "backgroundColor" => "rgba(41, 137, 216, .9)"
     );

$data['labels'] = array("Eating", "Drinking", "Sleeping", "Designing", "Coding", "Cycling", "Running");

echo json_encode($data);

如前所述，一旦您构建了数组，json_encode 就会在此处为您完成所有工作

{
  "datasets": [
    {
      "label": "First Data Set",
      "borderColor": "rgba(30, 87, 153, .9)",
      "backgroundColor": "rgba(30, 87, 153, .5)"
    },
    {
      "label": "Second Data Set",
      "borderColor": "rgba(41, 137, 216, .9)",
      "backgroundColor": "rgba(41, 137, 216, .9)"
    }
  ],
  "labels": [
    "Eating",
    "Drinking",
    "Sleeping",
    "Designing",
    "Coding",
    "Cycling",
    "Running"
  ]
}