【发布时间】:2017-06-08 16:54:06
【问题描述】:
这是一些可重现的代码。我想知道当特征被单热编码时,每个特征的 SE 计算是什么。如果我要自己尝试:
看起来有些 SE 是 1,我猜这意味着重建 100% 确定这是一回事,但实际上是另一回事。对于分数误差,它们是否代表了softmax分类器分配给类别的概率的不同程度的错误?
library(h2o)
art <- data.frame(a = c("a","b","a","c","d","e","g","f","a"),
b = c("b","c","d","e","b","c","d","e","b"),
c = c(4,3,2,5,6,1,2,3,5))
dl = h2o.deeplearning(x = c("a","b","c"), training_frame = as.h2o(art),
autoencoder = TRUE,
reproducible = T,
seed = 1234,
hidden = c(1), epochs = 1)
sus.anon = h2o.anomaly(dl, as.h2o(art), per_feature=TRUE)
【问题讨论】:
标签: r h2o autoencoder