使用 os.listdir(path) 时无法打开文件

Question

for file in os.listdir(path):
try:
    with open(file, 'r') as fp:
        msg = MIMEBase('application', "octet-stream")
        msg.set_payload(fp.read())
    encoders.encode_base64(msg)
    msg.add_header('Content-Disposition', 'attachment', filename=os.path.basename(file))
    outer.attach(msg)
except:
    print("Unable to open one of the attachments. Error: ", sys.exc_info()[0])
    raise

composed = outer.as_string()

我收到“FileNotFoundError: [Errno 2] No such file or directory”，但文件存在！可能是 os.listdir() 对象类型？

Answer 1

os.listdir 函数只返回文件名。您应该连接路径和文件名：

for file in os.listdir(path):
    try:
        with open(ps.path.join(path, file), 'r') as fp:
    ...