【发布时间】:2010-06-09 19:02:32
【问题描述】:
在使用 Symfony 1.4 定义一对多关系时,我遇到了意想不到的行为(对我来说!)。这是一个演示行为的简单示例,有一个 Employer 表和一个 Employee 表:一个 Employer 可以有多个 Employees。 YML架构文件如下:
Employee:
columns:
id: { type: integer, primary: true, autoincrement: true }
first_name: { type: string(30), notnull: true }
last_name: { type: string(30), notnull: true }
employer_id: { type: integer }
relations:
Employer:
local: employer_id
foreign: id
type: one
foreignType: many
foreignAlias: Workers
Employer:
columns:
id: { type: integer, primary: true, autoincrement: true }
name: { type: string(100) }
line1: { type: string(100) }
city: { type: string(100) }
state: { type: string(10) }
因此,在 Employer 上调用 getWorkers() 应该返回与 Employer 关联的员工。当getWorkers() 第一次被调用时,我得到了这个预期的行为。
但是,在后续调用中,如果已向雇主添加了额外的员工(以编程方式或直接在数据库 [MySQL] 中),getWorkers() 调用仍会返回第一个结果。
我已通过单步执行 getWorkers() 调用的 Symfony 源来验证,在后续调用中,它会返回存储在 _references 数组中的缓存值。
如果我以编程方式跟踪外键,通过employee_id 查询Employee,那么我会得到完整的结果集。
谁能解释这种行为?
这是我在“动作”中运行的一些示例 PHP 代码,它演示了行为:
// Create common employer.
$employer = new Employer();
$employer->setName("My Employer");
$employer->setLine1("100 Main Street");
$employer->setCity("AnyTown");
$employer->setState("State");
$employer->save();
// Create two employees,
$worker1 = new Employee();
$worker1->setFirstName("John");
$worker1->setLastName("Doe");
$worker1->setEmployer($employer);
$worker1->save();
$worker2 = new Employee();
$worker2->setFirstName("Jane");
$worker2->setLastName("Smith");
$worker2->setEmployer($employer);
$worker2->save();
$myEmployer = Doctrine_Core::getTable('Employer')->findOneBy('name', 'My Employer');
$workers = $myEmployer->getWorkers();
echo "Number of workers for " . $myEmployer->getName() . ' is ' . count($workers);
// This gives the expected 2 employees.
// Now create another employee in the common employer.
$worker3 = new Employee();
$worker3->setFirstName("Anne");
$worker3->setLastName("Droid");
$worker3->setEmployer($employer);
$worker3->save();
$myEmployer = Doctrine_Core::getTable('Employer')->findOneBy('name', 'My Employer');
$workers = $myEmployer->getWorkers();
echo "Number of workers for " . $myEmployer->getName() . ' is ' . count($workers);
// This still gives 2 employees, whereas there are 3 in the DB.
// Follow FK directly.
$workers = Doctrine_Core::getTable('Employee')->findBy('employer_id', $myEmployer->getId());
echo "Number of workers for " . $myEmployer->getName() . ' is ' . count($workers);
// This gives the expected 3 employees.
如何强制它每次都重新关注关系?
【问题讨论】:
标签: php caching symfony1 one-to-many symfony-1.4