【问题标题】:Get only NEW Emails imaplib and python只获取新的电子邮件 imaplib 和 python
【发布时间】:2012-10-24 00:39:27
【问题描述】:

这是一个更大项目的一小部分。我只需要获取未读电子邮件并解析它们的标题。如何修改以下脚本以仅获取未读电子邮件?

conn = imaplib.IMAP4_SSL(imap_server)
conn.login(imap_user, imap_password)

status, messages = conn.select('INBOX')    

if status != "OK":
    print "Incorrect mail box"
    exit()

print messages

【问题讨论】:

  • 我忘了还要求提供电子邮件的正文。

标签: python imaplib


【解决方案1】:

你可以使用 imap_tools 包: https://pypi.org/project/imap-tools/

from imap_tools import MailBox, AND
with MailBox('imap.mail.com').login('test@mail.com', 'password', 'INBOX') as mailbox:
    # get unseen emails from INBOX folder
    for msg in mailbox.fetch(AND(seen=False)):
        print(msg.date, len(msg.html or msg.text))

【讨论】:

    【解决方案2】:

    上面的答案实际上不再起作用,或者可能从未起作用,但我对其进行了修改,因此它只返回看不见的消息,它曾经给出:错误无法解析 fetch 命令或类似的东西,这是一个工作代码:

    mail = imaplib.IMAP4_SSL('imap.gmail.com')
    (retcode, capabilities) = mail.login('email','pass')
    mail.list()
    mail.select('inbox')
    
    n=0
    (retcode, messages) = mail.search(None, '(UNSEEN)')
    if retcode == 'OK':
    
       for num in messages[0].split() :
          print 'Processing '
          n=n+1
          typ, data = mail.fetch(num,'(RFC822)')
          for response_part in data:
             if isinstance(response_part, tuple):
                 original = email.message_from_string(response_part[1])
    
                 print original['From']
                 print original['Subject']
                 typ, data = mail.store(num,'+FLAGS','\\Seen')
    
    print n
    

    我认为错误来自messages[0].split(' '),但上面的代码应该可以正常工作。

    另外,请注意 +FLAGS 而不是 -FLAGS,它将邮件标记为已读。

    编辑 2020:如果您在 python 2.7 死亡后在 2020 年路过:将 email.message_from_string(data[0][1]) 替换为 email.message_from_bytes(data[0][1])

    【讨论】:

    • 当然,别忘了导入imaplibemail
    • 如何从 original 获取邮件正文?
    【解决方案3】:

    这样的事情就可以解决问题。

    conn = imaplib.IMAP4_SSL(imap_server)
    
    try:
        (retcode, capabilities) = conn.login(imap_user, imap_password)
    except:
        print sys.exc_info()[1]
        sys.exit(1)
    
    conn.select(readonly=1) # Select inbox or default namespace
    (retcode, messages) = conn.search(None, '(UNSEEN)')
    if retcode == 'OK':
        for num in messages[0].split(' '):
            print 'Processing :', message
            typ, data = conn.fetch(num,'(RFC822)')
            msg = email.message_from_string(data[0][1])
            typ, data = conn.store(num,'-FLAGS','\\Seen')
            if ret == 'OK':
                print data,'\n',30*'-'
                print msg
    
    conn.close()
    

    这里还有一个重复的问题 - Find new messages added to an imap mailbox since I last checked with python imaplib2?

    两个有用的函数,用于检索您检测到的新邮件的正文和附件(参考:How to fetch an email body using imaplib in python?) -

    def getMsgs(servername="myimapserverfqdn"):
      usernm = getpass.getuser()
      passwd = getpass.getpass()
      subject = 'Your SSL Certificate'
      conn = imaplib.IMAP4_SSL(servername)
      conn.login(usernm,passwd)
      conn.select('Inbox')
      typ, data = conn.search(None,'(UNSEEN SUBJECT "%s")' % subject)
      for num in data[0].split():
        typ, data = conn.fetch(num,'(RFC822)')
        msg = email.message_from_string(data[0][1])
        typ, data = conn.store(num,'-FLAGS','\\Seen')
        yield msg
    
    def getAttachment(msg,check):
      for part in msg.walk():
        if part.get_content_type() == 'application/octet-stream':
          if check(part.get_filename()):
            return part.get_payload(decode=1)
    

    PS:如果在python 2.7死后2020年路过:把email.message_from_string(data[0][1])换成email.message_from_bytes(data[0][1])

    【讨论】:

    • 用两个新函数 getMsgsgetAttachment 更新了我的答案,然后您可以在 for message in messages[0].split(' '): for 循环中使用它们。
    • 关于将消息标记为已见的说明。将行 typ, data = conn.store(num,'-FLAGS','\\Seen') 更改为 typ, data = conn.store(num,'+FLAGS','\\Seen') 为我修复了它.
    • ret 定义在哪里?
    • 您的答案并非在所有情况下都有效。我尝试检查看不见的消息,看不见的消息列表中的第一条消息有['flags', ('RFC822', 'message'),而其他消息有[('RFC822', 'message')]。要么这是一些 IMAP 奇怪,要么 imaplib2 有一个奇怪的输出格式。
    • check() 是什么? Python 没有找到它
    【解决方案4】:

    我已经设法使用 Gmail 让它工作:

    import datetime
    import email
    import imaplib
    import mailbox
    
    
    EMAIL_ACCOUNT = "your@gmail.com"
    PASSWORD = "your password"
    
    mail = imaplib.IMAP4_SSL('imap.gmail.com')
    mail.login(EMAIL_ACCOUNT, PASSWORD)
    mail.list()
    mail.select('inbox')
    result, data = mail.uid('search', None, "UNSEEN") # (ALL/UNSEEN)
    i = len(data[0].split())
    
    for x in range(i):
        latest_email_uid = data[0].split()[x]
        result, email_data = mail.uid('fetch', latest_email_uid, '(RFC822)')
        # result, email_data = conn.store(num,'-FLAGS','\\Seen') 
        # this might work to set flag to seen, if it doesn't already
        raw_email = email_data[0][1]
        raw_email_string = raw_email.decode('utf-8')
        email_message = email.message_from_string(raw_email_string)
    
        # Header Details
        date_tuple = email.utils.parsedate_tz(email_message['Date'])
        if date_tuple:
            local_date = datetime.datetime.fromtimestamp(email.utils.mktime_tz(date_tuple))
            local_message_date = "%s" %(str(local_date.strftime("%a, %d %b %Y %H:%M:%S")))
        email_from = str(email.header.make_header(email.header.decode_header(email_message['From'])))
        email_to = str(email.header.make_header(email.header.decode_header(email_message['To'])))
        subject = str(email.header.make_header(email.header.decode_header(email_message['Subject'])))
    
        # Body details
        for part in email_message.walk():
            if part.get_content_type() == "text/plain":
                body = part.get_payload(decode=True)
                file_name = "email_" + str(x) + ".txt"
                output_file = open(file_name, 'w')
                output_file.write("From: %s\nTo: %s\nDate: %s\nSubject: %s\n\nBody: \n\n%s" %(email_from, email_to,local_message_date, subject, body.decode('utf-8')))
                output_file.close()
            else:
                continue
    

    【讨论】:

      【解决方案5】:
      original = email.message_from_string(response_part[1])
      

      需要更改为:

      original = email.message_from_bytes(response_part[1])
      

      【讨论】:

      • 这可能是 Python 3 的必要修复,但不会尝试回答 OP 的问题,而应该是评论,显然是参考Amro's answer
      猜你喜欢
      • 2012-12-11
      • 2017-04-04
      • 1970-01-01
      • 2015-04-29
      • 2011-09-06
      • 2015-04-17
      • 2011-01-14
      • 1970-01-01
      • 2014-10-03
      相关资源
      最近更新 更多