如何以编程方式将我自己的 ServletConfig 传递给 servlet

Question

这是一个关于从以下位置嵌入 jetty 7 的示例： http://wiki.eclipse.org/Jetty/Tutorial/Embedding_Jetty

public class OneServletContext
{
    public static void main(String[] args) throws Exception
    {
        Server server = new Server(8080);

        ServletContextHandler context = new ServletContextHandler(ServletContextHandler.SESSIONS);
        context.setContextPath("/");
        server.setHandler(context);

        context.addServlet(new ServletHolder(new HelloServlet()),"/*");

        server.start();
        server.join();
    }
}

服务器 HelloServlet 将通过调用 init(ServletConfig config) 进行初始化；

如何告诉 Jetty 将我自己的 ServletConfig 传递给 HelloServet？ （我没有 web.xml 文件，我也不想拥有）

Note:
I think that in Jetty6, you can call context.setInitParameter("my_key", "my_value");
but this function does not exists in Jetty7.

I've tried with context.getServletContext.setInitParameter("my_key", "my_value");
but I get an exception
java.lang.IllegalStateException was thrown.
org.eclipse.jetty.servlet.ServletContextHandler$Context.setInitParameter(ServletContextHandler.java:569)

Answer 1

已解决：

ServletHolder helloServletHolder = new ServletHolder(new HelloServlet());
helloServletHolder.setInitParameter("my_key", "my_value");
context.addServlet(helloServletHolder,"/*");