艰难地学习 Python argv 和 file

Question

过去几周我正在学习 python

from sys import argv
script,filename = argv 
print "We're delete the file %r" %filename
print "If you want to stop ctrl+c (^c)"
print "Please hit enter to continue"
raw_input(">_")
print "Opening file..."
filen = open(filename,'w')
print "Truncating your file...."
filen.truncate()
print "now in your file %r" %filen
print "Writing time write  something to your file"

line = raw_input("?")
print "write in progress..."
filen.write(line)
filen.write("\n end of document\n")
filen.close()

我想查看文件的内容，但是当我使用print filename 或print filen 时，它会显示名称并在变量filen 上打开文件

Answer 1

您可以使用filen.read()或filen.readline()或filen.readlines()读取数据

1) 阅读

fo = open(filename,read)
fo.seek(0, 0) #seek is used to change the file position.This requires only for read method
fo.read(10) #This reads 1st 10 characters
fo.close()

2) 读取行

fo = open(filename,read)
fo.readline() #This will read a single line from the file. You can add for loop to iterate all the data
fo.close()

3) 阅读线。

fo = open(filename,read)
fo.readline() #read all the lines of a file in a list 
fo.close()

下面的文档会给你更好的主意。 https://docs.python.org/2/tutorial/inputoutput.html

Answer 2

如果要打印打开的文件的内容，只需使用：print filen.read()。

Answer 3

最简单的：

from sys import argv
script,filename = argv 
with open(filename) as f:
    print f.readlines()

转储文件内容 或：

from sys import argv
script,filename = argv 
with open(filename) as f:
    lines=f.readlines()
for line in lines:
    print line

1×1 打印行