【发布时间】:2014-07-23 12:28:56
【问题描述】:
我有一个 Spring 3 应用程序,它通过非 RabbitMQ 接收器接收消息,处理它们并通过 RabbitMQ 转发。每次要发送消息时,都会建立一个新的 RabbitMQ 连接。这似乎有点浪费。我只是想知道这是否真的有必要,或者是否有原因不能在单例中保持连接并且只构建一次(用于多次发送)。这是发送方式:
private void send(String routingKey, String message) throws Exception {
String exchange = applicationConfiguration.getAMQPExchange();
String ipAddress = applicationConfiguration.getAMQPHost();
String exchangeType = applicationConfiguration.getAMQPExchangeType();
String password = applicationConfiguration.getAMQPUser();
String user = applicationConfiguration.getAMQPPassword();
String virtualHost = applicationConfiguration.getAMQPVirtualHost();
String port = applicationConfiguration.getAMQPPort();
ConnectionFactory factory = new ConnectionFactory();
factory.setUsername(user);
factory.setPassword(password);
factory.setVirtualHost(virtualHost);
factory.setPort(Integer.parseInt(port));
factory.setHost(ipAddress);
Connection connection = factory.newConnection();
Channel channel = connection.createChannel();
channel.exchangeDeclare(exchange, exchangeType);
channel.basicPublish(exchange, routingKey, null, message.getBytes());
log.debug(" [AMQP] Sent message with key {} : {}",routingKey, message);
connection.close();
}
或者一个可能的单例:
public class MyConnection {
private static MyConnection singleton = new MyConnection();
private static Connection connection;
private MyConnection() {
ConnectionFactory factory = new ConnectionFactory();
String exchange = applicationConfiguration.getAMQPExchange();
String ipAddress = applicationConfiguration.getAMQPHost();
String exchangeType = applicationConfiguration.getAMQPExchangeType();
String password = applicationConfiguration.getAMQPUser();
String user = applicationConfiguration.getAMQPPassword();
String virtualHost = applicationConfiguration.getAMQPVirtualHost();
String port = applicationConfiguration.getAMQPPort();
try {
factory.setUsername(user);
factory.setPassword(password);
factory.setVirtualHost(virtualHost);
factory.setPort(Integer.parseInt(port));
factory.setHost(ipAddress);
connection = factory.newConnection();
}
catch (Exception e) {
e.printStackTrace();
}
}
public static Connection getInstance( ) {
return connection;
}
}
【问题讨论】:
-
没有。至少在没有连接或套接字级别错误的情况下。