从另一个函数调用一个函数内部定义的变量的更简单方法

Question

假设我有很多变量，而不是每次都写在()里面，有没有更简单的方法将所有变量压缩成一个单词？

def numbers():
    a = 1
    b = 2
    c = 3
    d = 4
    e = 5
    f = 6
    g = 7
    h = 8
    i = 9

    new_variable(a, b, c, d, e, f, g, h, i)


def new_variable(a, b, c, d, e, f, g, h, i):
    j = g + i
    print (j)
    new_variable_2(a, b, c, d, e, f, g, h, i)

def new_variable_2(a, b, c, d, e, f, g, h, i):
    k = g + h
    print (k)
    new_variable_3(a, b, c, d, e, f, g, h, i)

    def new_variable_3(a, b, c, d, e, f, g, h, i):
    l = h + i
    print (i)

numbers()

Answer 1

你可以这样试试：

a, b, c, d, e, f, g, h, i = range(1,10)
alphabet = [a, b, c, d, e, f, g, h, i]

def new_variable(*alphabet):
    j = g + i
    print (j)
    new_variable_2(*alphabet)

def new_variable_2(*alphabet):
    k = g + h
    print (k)
    new_variable_3(*alphabet)

def new_variable_3(*alphabet):
    l = h + i
    print (i)

new_variable(*alphabet)

返回与您的代码相同的数字。