在 Python 中拆分结果以获取 CPU 使用率

Question

现在已经尝试让它工作了几个小时。我没有尝试将这段文字分开。我只想要当前的 CPU

>>> from __future__ import print_function
>>> from urllib.request import urlopen
>>> import json
>>> import subprocess
>>> import requests
>>> import random
>>> import sys
>>> import os
>>> import time
>>> import datetime
>>> import MySQLdb as my
>>> import psutil
>>> os.popen('vcgencmd measure_temp').readline()
"temp=52.0'C\n"
>>> cpu = psutil.cpu_freq()
>>> cpu = cpu.split('current=')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'scpufreq' object has no attribute 'split'
>>> psutil.cpu_freq()
scpufreq(current=600.0, min=600.0, max=1500.0)
>>> psutil.cpu_freq(percpu=True)
[scpufreq(current=600.0, min=600.0, max=1500.0)]
>>> cpu = psutil.cpu_freq(percpu=True)
>>> cpu.split('=')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'list' object has no attribute 'split'
>>> AttributeError: 'list' object has no attribute 'split'
  File "<stdin>", line 1
    AttributeError: 'list' object has no attribute 'split'
                                ^
SyntaxError: invalid syntax
>>> AttributeError: 'list' object has no attribute 'split'
  File "<stdin>", line 1
    AttributeError: 'list' object has no attribute 'split'
                                ^
SyntaxError: invalid syntax
>>> psutil.cpu_freq(percpu=True).readline()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'list' object has no attribute 'readline'
>>> cpu = psutil.cpu_freq()

我哪里错了？

操作系统：Rasbian Buster 蟒蛇：python3 画中画：pip3

Answer 1

看起来您似乎忽略了错误消息：

>>> cpu = psutil.cpu_freq()
>>> cpu = cpu.split('current=')
Traceback (most recent call last):
 File "<stdin>", line 1, in <module>
AttributeError: 'scpufreq' object has no attribute 'split'

psutil.cpu_freq() 的返回值不是字符串，因此它没有 split 方法。如果您只是打印值...

>>> cpu
scpufreq(current=700.0, min=700.0, max=800.0)

...您对它具有哪些属性有所了解，实际上，我们可以像这样访问这些值：

>>> cpu.current
700.0
>>> cpu.max
800.0

当您设置percpu=True 时，您将返回一个列表：

>>> psutil.cpu_freq(percpu=True)
[scpufreq(current=600.0, min=600.0, max=1500.0)]

再一次，list 不是字符串，所以没有 split 方法。由于只有一个 CPU，因此您会返回一个 1 项列表，因此您可以像这样访问值：

>>> cpu = psutil.cpu_freq(percpu=True)
>>> cpu[0].current
700.0