使用我的 python 脚本获取多条错误消息

Question

我有一个 python 脚本，我正在尝试读取目录中的所有 .txt 文件，并确定它们是否针对我脚本中的任何条件返回 True 或 False。我收到了一些我在下面列出的错误消息。我希望脚本读取包含格式为 .json 格式的文本的 .txt 文件。然后我希望脚本确定 .txt 文件是否与下面代码中的任何语句匹配。然后我想将结果输出到 csv 文件。非常感激您的帮忙！第二条错误消息没有任何意义，因为我在路径中指定的目录中有 .json 格式的 .txt 文件。

File "C:/Users/xxx/Documents/best_version_of_vt_checker.py", line 34, in <module>
    print(vt_result_check(path))
  File "C:/Users/xxx/Documents/best_version_of_vt_checker.py", line 10, in vt_result_check
    with open(filename, 'r') as vt_result_file:
FileNotFoundError: [Errno 2] No such file or directory: '.2500.c.dynadns.eu.txt'

import os
import json

path=r'./output/'


def vt_result_check(path):
    vt_result = False
    for filename in os.listdir(path):
        with open(filename, 'r') as vt_result_file:
            vt_data = json.load(vt_result_file)

        # Look for any positive detected referrer samples
        # Look for any positive detected communicating samples
        # Look for any positive detected downloaded samples
        # Look for any positive detected URLs
        sample_types = ('detected_referrer_samples', 'detected_communicating_samples',
                        'detected_downloaded_samples', 'detected_urls')
        vt_result |= any(sample['positives'] > 0 for sample_type in sample_types
                                                 for sample in vt_data.get(sample_type, []))

        # Look for a Dr. Web category of known infection source
        vt_result |= vt_data.get('Dr.Web category') == "known infection source"

        # Look for a Forecepoint ThreatSeeker category of elevated exposure
        # Look for a Forecepoint ThreatSeeker category of phishing and other frauds
        # Look for a Forecepoint ThreatSeeker category of suspicious content
        threats = ("elevated exposure", "phishing and other frauds", "suspicious content")
        vt_result |= vt_data.get('Forcepoint ThreatSeeker category') in threats

    return vt_result

if __name__ == "__main__":
    print(vt_result_check(path))
    with open(csvpath, 'w') as csvfile:
        writer.writerow([vt_result_check()])

再次出现错误消息*

File "C:/Users/bwerner/Documents/3pm_reporter.py", line 34, in <module>
    print(vt_result_check(path))
  File "C:/Users/bwerner/Documents/3pm_reporter.py", line 11, in vt_result_check
    vt_data = json.load(vt_result_file)
  File "C:\Users\bwerner\AppData\Local\Continuum\anaconda3\Lib\json\__init__.py", line 299, in load
    parse_constant=parse_constant, object_pairs_hook=object_pairs_hook, **kw)
  File "C:\Users\bwerner\AppData\Local\Continuum\anaconda3\Lib\json\__init__.py", line 354, in loads
    return _default_decoder.decode(s)
  File "C:\Users\bwerner\AppData\Local\Continuum\anaconda3\Lib\json\decoder.py", line 339, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Users\bwerner\AppData\Local\Continuum\anaconda3\Lib\json\decoder.py", line 357, in raw_decode
    raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Answer 1

您正在使用 os.listdir 来获取文件夹 output 中的所有文件。但是，当您尝试打开它们时，您只使用了文件名，没有 output 文件夹。您需要包含路径和文件名。

将with open(filename, 'r') as vt_result_file: 行替换为以下行：with open(path+filename, 'r') as vt_result_file:

这结合了路径和文件名，以便正确定位文件。