【发布时间】:2016-09-22 05:26:35
【问题描述】:
我有以下一组 python 3.5 代码:
from urllib.parse import unquote
import requests
company_code = '%2Fm%2F07gyp7'
company_code_unquoted = unquote(company_code)
search_params = {'gprop' : 'news' , 'q' : company_code_unquoted}
root_url = 'https://www.google.com/trends/explore'
request_link = requests.get(root_url , params = search_params)
company_spec_url = request_link.url
这只会转到麦当劳的谷歌趋势网页。我想下载这个 xpath 中趋势的 csv 文件:
CSV_file_xpath = "/html/body/div[2]/div[2]/md-content/div/div/div[1]/trends-widget/ng-include/widget/div/div/div[1]/widget-actions/div/button[3]/div"
有没有办法不使用硒?
【问题讨论】:
-
token 是动态生成的,所以没有 Js 就不会这样做
标签: python-3.x csv selenium python-requests urllib