如何从每个输出行中分离数据

Question

我从代码中获得了这些数据

list = [sno,state_name,active,positive,cured,death,new_active,new_positive,new_cured,new_death]
lol= [list]

def Extract(lol): 
    return [item[0] for item in lol] 
print(Extract(lol))

我想在这里为每个类别创建一个列表。一类用于数字，一类用于名称，一类用于第三组值，依此类推。我好像搞不懂。

[2, 'Andam', 635, 2985, 2309, 41, 602, 3018, 2374, 42]
[1, 'Andhr', 92208, 382469, 286720, 3541, 94209, 393090, 295248, 3633]
[3, 'Arunach', 987, 3555, 2563, 5, 1007, 3633, 2621, 5]
[4, 'Assama', 19535, 96771, 76962, 274, 19222, 98807, 79307, 278]
[5, 'Bira', 19823, 126714, 106361, 530, 19067, 128780, 109175, 538]
[6, 'Chandiga', 1539, 3376, 1796, 41, 1544, 3564, 1977, 43]
[7, 'Chargh', 10174, 24550, 14145, 231, 11136, 25988, 14607, 245]

Answer 1

一种方法是使用 enumerate() 遍历列表：

lst = [2, 'Andam', 635, 2985, 2309, 41, 602, 3018, 2374, 42]

numbers= []
state_name = []
for indx, elem in enumerate(lst):
    if indx == 0:
        numbers.append(elem)
    elif indx == 1:
        state_name.append(elem)

print(numbers)
print(state_name)

编辑：

如果这是一个嵌套列表，您可以将每个元素更改为str，然后通过索引获取第一个元素：

lst = [[2, 'Andam', 635, 2985, 2309, 41, 602, 3018, 2374, 42],
[2, 'Andam', 635, 2985, 2309, 41, 602, 3018, 2374, 42],
[1, 'Andhr', 92208, 382469, 286720, 3541, 94209, 393090, 295248, 3633],
[3, 'Arunach', 987, 3555, 2563, 5, 1007, 3633, 2621, 5],
[4, 'Assama', 19535, 96771, 76962, 274, 19222, 98807, 79307, 278],
[5, 'Bira', 19823, 126714, 106361, 530, 19067, 128780, 109175, 538],
[6, 'Chandiga', 1539, 3376, 1796, 41, 1544, 3564, 1977, 43],
[7, 'Chargh', 10174, 24550, 14145, 231, 11136, 25988, 14607, 245]]

# convert it to list of str
lst_new =[[str(x) for x in lst] for lst in lst]

numbers = [x[0] for x in lst_new]
state_names = [x[1] for x in lst_new]
# print(numbers)
print([int(x) for x in numbers])  # if you want it back in `int`
print(state_names)

输出：

[2, 2, 1, 3, 4, 5, 6, 7]
['Andam', 'Andam', 'Andhr', 'Arunach', 'Assama', 'Bira', 'Chandiga', 'Chargh']