【发布时间】:2021-06-10 16:14:16
【问题描述】:
我从 API 获得数据 json,我想将它们存储到我的数据库中。
数据 json 样本:
{
"success": true,
"data": [
{
"status_employee_id": "1",
"name": "Manager"
},
{
"status_employee_id": "2",
"name": "Staff"
},
{
"status_employee_id": "3",
"name": "OB"
},
{
"status_employee_id": "4",
"name": "Fired"
},
{
"status_employee_id": "5",
"name": "Retired"
}
]
}
我的模型
class StatusEmployee extends Model
{
use HasFactory;
protected $table = 'status_employee';
protected $fillable = [
'status_employee_id','name'
];
public $timestamps = false;
}
我已经尝试在我的控制器中使用它
public function store()
{
$client = new \GuzzleHttp\Client();
$res = $client->request('GET', 'http://xx.xx.xx.xx/tools/public/get_status_employee');
$datas = json_decode($res->getBody(), true);
foreach($datas as $data){
StatusEmployee::create([
'status_employee_id' => $data->status_employee_id,
'name' => $data->name,
]);
}
}
我想将数据 json 样本存储到我的表 status_employee。如何制作?
【问题讨论】:
-
到目前为止你尝试过什么?问题是什么?
标签: laravel api rest laravel-8