从长文本中提取子字符串

Question

我有一个字符串：

string="
(2021-07-04 11:58:43 PM BST)  
---  
le  ) says tosen  

你好，你好

(2021-07-05 12:04:42 AM BST)  
---  
len (Trade ) says to sen  
okay -5 / 0  .



(2021-07-04 11:47:14 PM BST)  
---  
Keun says to
HanSo 
hello 
  
  
  
  
--- 


  
  

(2021-07-05 12:09:41 AM BST)  
---  
len (Trade) says to sen  
yes -5 / 0 TN -- / +2.5  
  
  
---  
  
* * *

Processe | 2021-07-05 12:26:44 AM
BST  
---

"

我只想提取says to之后和timestamp之前的文本。

预期输出为：

text=['yoh Hi yo','sen OK -5 / 0','sen yes -5 / 0 TN -- / +2.5']

我尝试过的：

text=re.findall(r'表示为 (\D+)(',string)

Answer 1

says to和括号之间的下一个时间戳之间有数字，所以使用\D+会在有数字时停止匹配。

相反，您可以在匹配组 1 中的 says to 后捕获所有以下不以 ( 和数字或 --- 开头的行（或使其更具体）

\bsays to (.*(?:\n(?!\(\d|---).*?)*?)\s*\n(?:\(\d|---)

Regex demo | Python demo

例如：

pattern = r"\bsays to (.*(?:\n(?!\(\d|---).*?)*?)\s*\n(?:\(\d|---)"
text = re.findall(pattern, text)
print(text)

输出

['yohan sen  \n[[:Conversations will be recorded and may be monitored by the participants and\ntheir employers:]] Hi yohan', 'yohan sen  \nokay -5 / 0', 'yohan sen  \nyes -5 / 0 TN -- / +2.5']