用python逐点拆分列表答案

【问题标题】：split a list a sentence by point with python用python逐点拆分列表
【发布时间】：2019-05-15 10:52:31
【问题描述】：

我有一个句子列表：

['hello', 'I would like to thank you', 'I would like to thank you. By the way']

当我找到“。”时，我需要将每个句子分成列表。 .

例如，在上面的例子中，预期的结果是：

['hello', 'I would like to thank you', 'I would like to thank you'. 'By the way']

我在 python 中尝试使用这段代码：

def split_pint(result):
    for i in result:
        i = re.split(r". ", i)
    return result

但是句子没有被拆分。

有什么想法吗？

谢谢

【问题讨论】：

标签： python regex python-3.x

【解决方案1】：

使用简单的迭代和str.split

例如：

data = ['hello', 'I would like to thank you', 'I would like to thank you. By the way']

def split_pint(data):
    result = []
    for elem in data:
        result.extend(elem.split(". "))        
    return result

print(split_pint(data))

输出：

['hello', 'I would like to thank you', 'I would like to thank you', 'By the way']

【讨论】：

【解决方案2】：

这不是修改列表的方式，如您所见：

l = [0, 0]
for x in l:
    x = 1
print(l)
# [0, 0]

无论如何，如果你想使用re.split，你需要转义. 字符：

import re

l = ['hello', 'I would like to thank you', 'I would like to thank you. By the way']
def split_pint(result):
    res = []
    for i in result:
        res += re.split("\. ", i)
    return res


print(split_pint(l))
['hello', 'I would like to thank you', 'I would like to thank you', 'By the way']

【讨论】：

【解决方案3】：

另一种选择，但单行且以函数式编程方式：

>>> from functools import reduce
>>> a = ['hello', 'I would like to thank you', 'I would like to thank you. By the way']
>>> reduce(lambda i, j: i + j, map(lambda s: s.split('. '), a))
['hello', 'I would like to thank you', 'I would like to thank you', 'By the way']

首先，map 从每个字符串中创建一个列表，其次，reduce 只是连接所有列表。

【讨论】：