请帮助用硒在表单框中输入文本

Question

我正在尝试编写教程并在 python 中学习 Selenium，但是我似乎无法让 Selenium 使用 find_element_by_class 或 find_element_by_XPATH 输入邮政编码。

我正在使用：

Python v3.9

Chrome v87

这是我正在练习的 URL（您可能需要在购物篮中添加一个测试项目才能看到按钮或运行脚本）：

https://www.currys.co.uk/app/checkout

这是我当前的点击代码：

# Selenium Tutorial #1

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains

import time

# Open Chromedriver
driver = webdriver.Chrome(r"C:\Users\Ste1337\Desktop\chromedriver\chromedriver.exe")

# Open webpage
driver.get("https://www.currys.co.uk/gbuk/tv-and-home-entertainment/televisions/televisions/samsung-ue75tu7020kxxu-75-smart-4k-ultra-hd-hdr-led-tv-10213562-pdt.html")

# Click "Accept All Cookies" or ignore if no pop up
try:
    element = WebDriverWait(driver, 10).until(
    EC.presence_of_element_located((By.ID, "onetrust-accept-btn-handler"))
    )
    element.click()
except Exception:
    pass

# Wait 3 seconds
driver.implicitly_wait(3)

# Click "Add to Basket" or refresh page if out of stock
try:
    element = WebDriverWait(driver, 1).until(
    EC.presence_of_element_located((By.XPATH, "email-desktop"))
    )
    time.sleep(5)
    browser.refresh()
except:
    button = driver.find_element_by_css_selector("button.Button__StyledButton-bvTPUF.hZIOeU.Button-jyKNMA.GZkwS")
    driver.execute_script("arguments[0].click();", button)

# Wait 3 seconds
driver.implicitly_wait(3)

# Click "Continue to Basket"
button = driver.find_element_by_css_selector("button.Button__StyledButton-bvTPUF.hZIOeU.Button-jyKNMA.sc-fzpjYC.gJohPa")
driver.execute_script("arguments[0].click();", button)

# Wait 3 seconds
driver.implicitly_wait(3)

# Click "Go to checkout"
button = driver.find_element_by_xpath("//button[contains(@data-component, 'Button')][contains(@type, 'button')]")
driver.execute_script("arguments[0].click();", button)

# Type in postcode
search = driver.find_element_by_xpath("//input[contains(@aria-invalid), 'False')][contains@aria-label, 'Postcode Checker')]")
search.send_keys(NG229NU)
search.send_keys(Keys.RETURN)

Answer 1

要识别input 元素，请使用locator 之一。

XPATH：

//input[@aria-label='Postcode Checker' and @type='search']

---

CSS 选择器：

input[aria-label='Postcode Checker'][type='search']

---

为避免同步问题，我建议使用WebDriverWait() 并等待element_to_be_clickable() 并在输入 框中输入文本。

search=WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"//input[@aria-label='Postcode Checker' and @type='search']")))
search.send_keys("NG229NU")
search.send_keys(Keys.RETURN)

Answer 2

您的 XPath 无效（第一个谓词中有额外的括号，而第二个谓词中没有左括号）。尝试替换

"//input[contains(@aria-invalid), 'False')][contains@aria-label, 'Postcode Checker')]"

与

"//input[contains(@aria-invalid, 'False')][contains(@aria-label, 'Postcode Checker')]"