Python按姓氏排序字典列表答案

【问题标题】：Python sort list of dictionary by last namePython按姓氏排序字典列表
【发布时间】：2017-10-31 04:51:59
【问题描述】：

我正在尝试对 dep_list 进行排序，这是一个包含员工信息（姓名、部门、职位、薪水）的字典列表。现在我相信我按名字排序，但是我想按姓氏排序。尽可能不将“名称”分成 2 个不同的字符串。

#Function for adding employee information
def add_emp():
    #Ask the user to add an employee
    print("Enter the employee's information:\n")
    #Input first and last name
    name = str(input("What is the employee's name? ")).title()
    #Input employee position
    position = str(input("What is their position? ")).title()
    #Input employee department
    em_department = str(input("What is their department? ")).title()
    #Make sure the salary is numeric
    try:
        #Input employee salary
        salary = round(float(input("What is their salary? ")), 2)
        #Add information to a dictionary called employees
        employees[name] = {"name": name, "position": position,     "em_department": em_department, "salary": salary}
    except:
        print("Salaries must be numeric, silly!")

#Function for adding employees to dictionary by department
def dep_emp():
    #Go through all department names stored in the tuple
    for x in dep_tup:
        #Initialize department list each time to ensure correct sorting
        dep_list = []
        #Go through all employee dictionaries; when matched, add to the list associated with the corresponding key in the dep_dict dictionary
        for names in employees:
            if x == employees[names]["em_department"]:
                dep_list.append(employees[names])
                dep_list.sort(key=operator.itemgetter('name'))
                dep_dict[x] = dep_list
                continue

注意：字典列表如下所示： {

department1: [{'name': 姓名, 'em_department': 部门, 'position': 职位, 'salary': 薪水}, ...],

部门 2：[...]

}

【问题讨论】：

标签： python python-3.x sorting dictionary

【解决方案1】：

dep_list.sort(key=lambda x: x['name'].split()[-1])

对于dep_list 中的每个字典，找到与name 键关联的值，对其进行拆分，并根据拆分中的最后一个字符串（应该是姓氏）进行排序。

【讨论】：