【发布时间】:2020-10-13 08:01:24
【问题描述】:
我正在尝试访问嵌套字典,问题是字典中的每个 obj 都有不同的数字和密钥,其中的一个也是如此,这是 json 源:
{
"100": {
"status": {
"timestamp": "2020-10-12T23:24:26.146Z",
"error_code": 0,
"error_message": null,
"elapsed": 19,
"credit_count": 1,
"notice": null
},
"data": {
"100": {
"id": 100,
"name": "Particle",
"symbol": "PRT",
"category": "coin",
"description": "/`enter code here`",
"slug": "particle",
"logo": "https://s2.coinmarketcap.com/static/img/coins/64x64/100.png",
"subreddit": "",
"notice": "",
"tags": ["mineable"],
"tag-names": ["Mineable"],
"tag-groups": ["OTHER"],
"urls": {
"website": ["http://www.bitparticle.com/"],
"twitter": [],
"message_board": [],
"chat": [],
"explorer": ["http://chaincollider.bitparticle.com/chain/Particle/"],
"reddit": [],
"technical_doc": [],
"source_code": [],
"announcement": []
},
"platform": null,
"date_added": "2014-01-22T00:00:00.000Z",
"twitter_username": "",
"is_hidden": 0
}
}
}
我正在尝试访问符号和徽标,我通过键入仅对 1 个 obj 进行了访问
json_file['100']['data']['100']['symbol']
我的最终目标是拥有一个完整的列表,其中包含每个 obj 的徽标和符号。
【问题讨论】:
-
如果您想要一个包含所有值的列表,请遍历键:
for k1 in json_file: for k2 in json_file[k1]['data']: x = json_file[k1]['data'][k2]['symbol'] ... -
有效,感觉真好!非常感谢
标签: python json python-3.x dictionary nested