将单个字典转换为字典列表并对其进行迭代答案

【问题标题】：converting individual dictonary to list of dictonary and iterating over it将单个字典转换为字典列表并对其进行迭代
【发布时间】：2021-04-30 10:08:55
【问题描述】：

我正在使用 nsepython 库，我想在其中迭代每个 openInterest 键并检查该键的前 3 个值并打印行使价、OI、交易量、changeinopenInterest。但是当我为特定脚本提取数据时，它会为每个执行价格提供单独的字典，我无法对其进行迭代。

{
  "strikePrice": 2400,
  "expiryDate": "27-May-2021",
  "underlying": "TCS",
  "identifier": "OPTSTKTCS27-05-2021CE2400.00",
  "openInterest": 1,
  "changeinOpenInterest": 0,
  "pchangeinOpenInterest": 0,
  "totalTradedVolume": 0,
  "impliedVolatility": 0,
  "lastPrice": 0,
  "change": 0,
  "pChange": 0,
  "totalBuyQuantity": 5700,
  "totalSellQuantity": 11400,
  "bidQty": 5700,
  "bidprice": 635.75,
  "askQty": 11400,
  "askPrice": 785.45,
  "underlyingValue": 3077.3
}

【问题讨论】：

能贴出获取字典数据的代码吗？
from nsepython import* from pprint import pprint from nsepython import* print(option_chain("TCS"))
好的。似乎并非所有记录都包含PE 的值，如何处理？

标签： python-3.x loops dictionary stock

【解决方案1】：

我似乎收到了完整的执行价格列表，版本为 0.0.94 的 nsepython：

>>> import nsepython
>>> c = nsepython.option_chain('TCS')
>>> interests = [(rec.get('PE', {'openInterest': 0})['openInterest'], rec.get('PE', {'strikePrice': 0})['strikePrice'], rec.get('PE', {'totalTradedVolume': 0})['totalTradedVolume'], rec.get('PE', {'changeinOpenInterest': 0})['changeinOpenInterest']) for rec in c['records']['data']]
>>> interests.sort(reverse=True)  # sort by changeinOpenInterest
>>> interests[:3]  # get top 3 of (openInterest, strikePrice, totalTradedVolume, changeinOpenInterest)
[(1115, 3000, 1399, 18), (599, 3100, 1704, 12), (560, 2800, 156, -4)]

【讨论】：