从python文件访问json中的嵌套字典答案

【问题标题】：Accessing nested dictionary in json from python file从python文件访问json中的嵌套字典
【发布时间】：2020-03-12 06:08:18
【问题描述】：

我有一个 intent.json 文件

{"intents": [
    {"tag": "greeting",
     "patterns": ["Hi there", "How are you", "Is anyone there?", "Hello", "Good day"],
     "responses": ["Hello, thanks for asking", "Good to see you again", "Hi there, how can I help?"],
     "context": [""]
    },
    {"tag": "goodbye",
     "patterns": ["Bye", "See you later", "Goodbye", "Nice chatting to you, bye", "Till next time"],
     "responses": ["See you!", "Have a nice day", "Bye! Come back again soon."],
     "context": [""]
    }
    ]
}

我有一个python文件，其中以下函数获取句子的意图，输出如下

classify_local('Hello, good day!')

输出为

['greeting']

现在我想获取与标签问候语相对应的响应。我该怎么做？

【问题讨论】：

检查classify_local函数，它必须使用“tag”键返回值，您也可以更改/添加“responses”键。
这能回答你的问题吗？ Parsing Through Nested JSON Python
你期待什么输出？
patterns 中的第三个元素是标签greeting、"Hello", "Good day" 还是"Hello, good day!"？
所以你想要响应中的第一个元素？

标签： python json python-3.x dictionary

【解决方案1】：

这里有很多可能的漏洞，但考虑到预期的输出，这应该可以确定句子在提供有限 I/O 的情况下是什么类型的意图。

import string

def classify_local(text):
    # Separate out the phrases of the input text
    # "Hello, good day!" --> ['hello', 'good day']
    phrases = [
        s.translate(s.maketrans("", "", string.punctuation)).strip().lower()
        for s in text.split(",")
    ]

    # Find tags where all phrases are in patterns
    return [
        i["tag"]
        for i in intents_json["intents"]
        if all(j in [k.lower() for k in i["patterns"]] for j in phrases)
    ]


classify_local("Hello, good day!")

如果您想要更柔和的匹配，请将返回中的 all 替换为 any，但这在更广泛的数据集中不太可能是正确的。

请记住，当针对更大的数据集解析书面句子时，这一切都会很快崩溃。

【讨论】：

【解决方案2】：

你可以使用正则表达式：

import re


my_json = {"intents": [
    {"tag": "greeting",
     "patterns": ["Hi there", "How are you", "Is anyone there?", "Hello", "Good day"],
     "responses": ["Hello, thanks for asking", "Good to see you again", "Hi there, how can I help?"],
     "context": [""]
    },
    {"tag": "goodbye",
     "patterns": ["Bye", "See you later", "Goodbye", "Nice chatting to you, bye", "Till next time"],
     "responses": ["See you!", "Have a nice day", "Bye! Come back again soon."],
     "context": [""]}]}


pattern_tag = {'|'.join(d["patterns"]): d['tag'] for d in my_json["intents"]}

def classify_local(my_strig):
    for p, t in pattern_tag.items():
        if re.search(p, my_strig):
            return t

classify_local('Hello, good day!')

输出：

'greeting'

从您的 json 文件中读取：

import json

with open('intent.json') as f:
    my_json = json.load(f)

【讨论】：

【解决方案3】：

如果您只是想要标签 greeting 的所有响应中的第一个响应，那么它就是，

json_value = {
    "intents": [
        {
            "tag": "greeting",
            "patterns": ["Hi there", "How are you", "Is anyone there?", "Hello", "Good day"],
            "responses": ["Hello, thanks for asking", "Good to see you again", "Hi there, how can I help?"],
            "context": [""]
        },
        {
            "tag": "goodbye",
            "patterns": ["Bye", "See you later", "Goodbye", "Nice chatting to you, bye", "Till next time"],
            "responses": ["See you!", "Have a nice day", "Bye! Come back again soon."],
            "context": [""]
        }
    ]
}


for intent in json_value['intents']:
    if intent['tag'] == 'greeting':
        response = intent['responses'][0]
print(response)

【讨论】：

无论你的函数输入如何classify_local，你都会给出响应