带有列表的嵌套字典到 MultiIndex Pandas DataFrame答案

【问题标题】：Nested dictionary with lists to MultiIndex Pandas DataFrame带有列表的嵌套字典到 MultiIndex Pandas DataFrame
【发布时间】：2018-02-08 15:04:33
【问题描述】：

我已经尝试了我为嵌套字典找到的所有可能的解决方案，但无法使任何工作，因为我的字典是列表和字典的组合：

我从 Oandapyv20 得到这个结果：

{
    "positions": [
      {
        "instrument": "USD_TRY",
        "long": {
          "units": "19028",
          "averagePrice": "3.96627",
          "pl": "2619.1369",
          "resettablePL": "2619.1369",
          "financing": "-212.5055",
          "guaranteedExecutionFees": "0.0000",
          "tradeIDs": [
            "173664",
            "173783",
            "173785",
            "173787",
            "176966",
          ],
          "unrealizedPL": "-267.6793"
        },
        "short": {
          "units": "0",
          "pl": "0.0000",
          "resettablePL": "0.0000",
          "financing": "0.0000",
          "guaranteedExecutionFees": "0.0000",
          "unrealizedPL": "0.0000"
        },
        "pl": "2619.1369",
        "resettablePL": "2619.1369",
        "financing": "-212.5055",
        "commission": "0.0000",
        "guaranteedExecutionFees": "0.0000",
        "unrealizedPL": "-267.6793",
        "marginUsed": "951.4000"
      },
      {
        "instrument": "USD_MXN",
        "long": {
          "units": "7750",
          "averagePrice": "19.37866",
          "pl": "122.5599",
          "resettablePL": "122.5599",
          "financing": "-48.8715",
          "guaranteedExecutionFees": "0.0000",
          "tradeIDs": [
            "212492",
            "212494",
            "212496",
          ],
          "unrealizedPL": "-41.5788"
        },
        "short": {
          "units": "0",
          "pl": "0.0000",
          "resettablePL": "0.0000",
          "financing": "0.0000",
          "guaranteedExecutionFees": "0.0000",
          "unrealizedPL": "0.0000"
        },
        "pl": "122.5599",
        "resettablePL": "122.5599",
        "financing": "-48.8715",
        "commission": "0.0000",
        "guaranteedExecutionFees": "0.0000",
        "unrealizedPL": "-41.5788",
        "marginUsed": "387.5000"
      },
      {
        "instrument": "USD_NOK",
        "long": {
          "units": "0",
          "pl": "0.0000",
          "resettablePL": "0.0000",
          "financing": "0.0000",
          "guaranteedExecutionFees": "0.0000",
          "unrealizedPL": "0.0000"
        },
        "short": {
          "units": "-13200",
          "averagePrice": "7.65519",
          "pl": "4906.3941",
          "resettablePL": "4906.3941",
          "financing": "-90.9699",
          "guaranteedExecutionFees": "0.0000",
          "tradeIDs": [
            "214255",
            "214257",
            "214259",
            "214281"
          ],
          "unrealizedPL": "-390.0560"
        },
        "pl": "4906.3941",
        "resettablePL": "4906.3941",
        "financing": "-90.9699",
        "commission": "0.0000",
        "guaranteedExecutionFees": "0.0000",
        "unrealizedPL": "-390.0560",
        "marginUsed": "132.0000"
      }
    ],
    "lastTransactionID": "228573"
  }
}

如何将其转换为 Pandas DataFrame？

例如这给出了一个错误：

 df = pd.DataFrame.from_dict(x,orient='index')
 TypeError: Expected list, got str

还有这个：

reform = {(level1_key, level2_key, level3_key): values
    for level1_key, level2_dict in x.items()
    for level2_key, level3_dict in level2_dict.items()
    for level3_key, values      in level3_dict.items()}

AttributeError: 'list' object has no attribute 'items'

是否可以在不求助于包括 for 循环和 try & except 在内的绝望尝试的情况下将上述内容输入到 DataFrame 中？

提前致谢

【问题讨论】：

标签： python python-3.x pandas dictionary dataframe

【解决方案1】：

你只需要申请pd.Series几次

df=pd.DataFrame(d)
s=df.positions.apply(pd.Series)

v=s.short.apply(pd.Series)
t=s.long.apply(pd.Series)
Yourdf=pd.concat([df,v,s,t],1).drop(['short','positions','long'],1)

【讨论】：