os.system在python中多次打开同一个应用程序[重复]

Question

这个程序基本上是一个硬编码的个人助理，我用它来做一些基本的事情。 我告诉程序“打开 Firefox”，它完美地打开它，当我给出另一个命令时，让我们说“打开 Sublime”，它仍然会打开 Firefox。这是为什么？如果我没有要求它，我不希望它打开其他应用程序。发生这种情况是因为我正在运行应用程序，但我没有通过脚本关闭它，就像我按“X”并关闭窗口一样。真的坚持这个！

这是我的代码...

import speech_recognition as sr
import pyttsx3
import json
import random
import os
import subprocess

engine = pyttsx3.init('sapi5')
voices = engine.getProperty('voices')
engine.setProperty('voice', voices[1].id)

def text2speech(audio):
    engine.setProperty('rate', 180) # Sets speed percent can be more than 100
    engine.say(audio)
    engine.runAndWait()

def takeCommand():
    r = sr.Recognizer()

    with sr.Microphone() as source:
        r.adjust_for_ambient_noise(source)
        print('Listening...')
        r.pause_threshold = 1
        audio = r.listen(source)

    try:
        print('Recognizing...')
        query = r.recognize_google(audio, language = 'en-in')
        print('You: ', query)
    except Exception as e:
        print(e)
        print('Unable to recognize your voice.')
        return 'None'
    return query

def rubysays(key): # key is the tag or key element in the data.json which contains the responses
    length = len(data[key])
    # print(length)
    say_this = data[key][random.randint(0, length - 1)]
    return say_this

def startruby():
    query = takeCommand().lower()

    if 'open firefox' or 'pen firefox' or 'firefox' or 'fire fox' in query: # opens Visual Studio Code
        say_this = 'Opening Firefox Browser'
        print(say_this)
        text2speech(say_this)
        # os.startfile(r'C:\Program Files\Mozilla Firefox\firefox.exe')
        os.system(r'C:\Program Files\Mozilla Firefox\firefox.exe')
    
    elif 'open code' or 'pen code' in query: # opens Visual Studio Code
        say_this = 'Opening Visual Studio Code'
        print(say_this)
        text2speech(say_this)
        # os.startfile(r'C:\Program Files\Microsoft VS Code\Code.exe')
        os.system(r'C:\Program Files\Microsoft VS Code\Code.exe')
    
    elif 'open sublime' or 'pen sublime' or 'open sub lime' or 'pen sub lime'in query: # opens Sublime Text
        say_this = 'Opening Sublime Text'
        print(say_this)
        text2speech(say_this)
        # os.startfile(r'C:\Program Files\Sublime Text 3\sublime_text.exe')
        os.system(r'C:\Program Files\Sublime Text 3\sublime_text.exe')

    elif 'open cmd' or 'c m d' in query: # opens command prompt
        say_this = 'Opening Windows Terminal'
        print(say_this)
        text2speech(say_this)
        # os.startfile(r'C:\Users\JasonPC\AppData\Local\Microsoft\WindowsApps\wt.exe')
        os.system(r'C:\Users\JasonPC\AppData\Local\Microsoft\WindowsApps\wt.exe')

    elif 'open discord' or 'discord' in query: # opens Discord
        say_this = 'Opening Discord'
        print(say_this)
        text2speech(say_this)
        # os.startfile(r'C:\Users\JasonPC\AppData\Local\Discord\Update.exe')
        os.system(r'C:\Users\JasonPC\AppData\Local\Discord\Update.exe')
    
    elif 'open steam' or 'steam' in query: # opens Steam
        say_this = 'Opening Steam'
        print(say_this)
        text2speech(say_this)
        # os.startfile(r'C:\Program Files (x86)\Steam\steam.exe')
        os.system(r'C:\Program Files (x86)\Steam\steam.exe')
    
    elif 'open calculator' or 'calculator' in query: # opens Calculator
        say_this = 'Opening Calculator'
        print(say_this)
        text2speech(say_this)
        # os.startfile(r'C:\Windows\System32\calc.exe')
        os.system(r'C:\Windows\System32\calc.exe')
    
    elif 'open discord' or 'discord' in query: # opens Camera
        say_this = 'Opening Camera'
        print(say_this)
        text2speech(say_this)
        os.system('start microsoft.windows.camera:')
    
    elif 'whatsapp' or 'whats app' or 'whats up' or "what's app" or "what's up" in query: # opens WhatsApp
        say_this = 'Opening WhatsApp'
        print(say_this)
        text2speech(say_this)
        # os.startfile(r'C:\Users\JasonPC\AppData\Local\WhatsApp\WhatsApp.exe')
        os.system(r'C:\Users\JasonPC\AppData\Local\WhatsApp\WhatsApp.exe')


if __name__ == '__main__':
    # use the json
    f = open('data.json')  
    data = json.load(f)

    text2speech('Hey this is Ruby!')

    while True:
        query = takeCommand().lower()

        if 'ruby' in query or 'rubi' in query:
            say_this = rubysays('greeting')
            print('You:', say_this)
            text2speech(say_this)
            startruby()
        
        if 'bye' in query or 'goodbye' in query:
            say_this = rubysays('bye')
            print(say_this)
            text2speech(say_this)
            exit()

Answer 1

见How to test multiple variables against a single value?

行： if 'open firefox' or 'pen firefox' or 'firefox' or 'fire fox' in query: 如果字符串在查询中，则始终为真，因为您正在测试字符串而不是。

例如：

In [1]: query = "xxx"

In [2]: bool('open firefox' or 'pen firefox' or 'firefox' or 'fire fox' in query)
Out[2]: True

In [3]: bool('fire fox' in query)
Out[3]: False

In [4]: bool('open firefox')
Out[4]: True